The pairs are:
K, Kr - Same period
Be, Mg - Same group
Ni, Tc - Both are transition metals
B, Ge - Both are metaloids
Al, Pb - Both form inert oxides
Answer:
1) Length - Meter
2) Mass - Pound
3) Time - Minute
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Answer: KI, LiBr, MgS,GaN
Explanation:
Ionic sizes are the deciding factor in lattice energy. The smaller the ion, the higher the lattice energy. Since K+> Li+ and I- is larger than Br-, LiBr will have a higher lattice energy. The size of the sulphide ion is much smaller than the nitride ion but the Gallium is much smaller due to lanthanide contraction hence the answer.
You can Multiply the whole equation with 2 as it is the denomanot number of 7/2.Therefore,the denomanator will be canceled out with 2 and the number of 7/2 will become 7.
Steps by Steps solution:
C3H8+7/2O2→3CO+4H2OC3H8+72O2→3CO+4H2O
=2×(C3H8+7/2O2→3CO+4H2OC3H8+72O2→3CO+4H2O)
=2C3H8+7O2→6CO+8H2OC3H8+144O2→6CO+8H2O
