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lianna [129]
3 years ago
6

What is the value of the function at x=3

Mathematics
1 answer:
Damm [24]3 years ago
4 0

Answer:

4

Step-by-step explanation:

Since the line of the function is passing through the point (3, 4).

Here x = 3 and y = 4

So the value of the function at x=3 is 4.

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6x-y=8<br> 7x-y=9<br> Solve linear systems by Multiplying first
Sindrei [870]
The answer is (1,-2). Here’s the work

4 0
3 years ago
Round 14494 to the nearest thousand feet
klasskru [66]
14,000 because 494 would round down since it is not above 500.

7 0
3 years ago
Find the value of x.
Tatiana [17]

Answer: The answer is x = 6 units.

Step-by-step explanation: Please refer to the attached diagram

The diagram in the question shows two triangles placed on each other and for convenience sake has been labelled ABDCE. Triangle ABC is a right angled triangle, and so is triangle ADE. From the marks on the lines, we can infer that line AD is equal in measurement to line DB. Also line AE is equal in measurement to line EC.

Therefore we can see the similarity in both triangles, if AD and AE equals DB and EC, then it follows that DE equals BC.

Hence if AD = DB and

AE = EC, and

DE = BC

Then, x - 3 = ½x

(½x can also be expressed as x/2)

x - 3 = x/2

By cross multiplication we now have

2(x - 3) = x

2x - 6 = x

By collecting like terms we now have

2x - x = 6

x = 6

8 0
3 years ago
PLS HELP WILL MARK BRAINLIESTTT What is the solution to this inequality?
vagabundo [1.1K]

Answer:

  a.  x > 0.2

Step-by-step explanation:

In either order, subtract the left-side constant and divide by the x-coefficient.

  3x +2.4 > 3

  3x > 0.6 . . . . . . subtract 2.4

  x > 0.2 . . . . . . . divide by 3

__

or

  x + 0.8 > 1 . . . . divide by 3

  x > 0.2 . . . . . . . subtract 0.8

8 0
3 years ago
A) How many ways can 2 integers from 1,2,...,100 be selected
Anna007 [38]

Answer with explanation:

→Number of Integers from 1 to 100

                                            =100(50 Odd +50 Even)

→50 Even =2,4,6,8,10,12,14,16,...............................100

→50 Odd=1,3,,5,7,9,..................................99.

→Sum of Two even integers is even.

→Sum of two odd Integers is odd.

→Sum of an Odd and even Integer is Odd.

(a)

Number of ways of Selecting 2 integers from 50 Integers ,so that their sum is even,

   =Selecting 2 Even integers from 50 Even Integers , and Selecting 2 Odd integers from 50 Odd integers ,as Order of arrangement is not Important, ,

        =_{2}^{50}\textrm{C}+_{2}^{50}\textrm{C}\\\\=\frac{50!}{(50-2)!(2!)}+\frac{50!}{(50-2)!(2!)}\\\\=\frac{50!}{48!\times 2!}+\frac{50!}{48!\times 2!}\\\\=\frac{50 \times 49}{2}+\frac{50 \times 49}{2}\\\\=1225+1225\\\\=2450

=4900 ways

(b)

Number of ways of Selecting 2 integers from 100 Integers ,so that their sum is Odd,

   =Selecting 1 even integer from 50 Integers, and 1 Odd integer from 50 Odd integers, as Order of arrangement is not Important,

        =_{1}^{50}\textrm{C}\times _{1}^{50}\textrm{C}\\\\=\frac{50!}{(50-1)!(1!)} \times \frac{50!}{(50-1)!(1!)}\\\\=\frac{50!}{49!\times 1!}\times \frac{50!}{49!\times 1!}\\\\=50\times 50\\\\=2500

=2500 ways

7 0
3 years ago
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