Answer:
4) Long exposure to low-energy radiation could give the same dose as a short burst of high-energy radiation.
Explanation:
When it comes to ionizing radiation, absorption should be kept as low as reasonably achievable (ALARA). This can be achieved by control of time spent in the vicinity of the source, the distance to the source and the use of personal protective equipment (PPE).
A short burst of high-energy radiation releases or generates a high radiation dose in a short time frame. This can also be achieved due to long exposure to low-energy radiation, which results into the gradual accumulation of the dose.
Answer:
The period of the orbit is 12163.649 seconds.
Explanation:
What quantity are you looking for? I'll assume it's the orbital period.
The period, P, of an orbit in seconds is found from
P = 2π √[a³/(GM)]
where
a = the semimajor axis of an elliptical orbit, or the radius of a circular orbit
G = 6.67428e-11 m³ kg⁻¹ sec⁻²
M = the sum of the masses of Mars and the satellite
The mass of the satellite is presumably negligible.
M = 6.4191e+23 kg
a = 1.6 Rmars = 1.6 (3.397e+6 meters) = 5435200 m
Therefore,
P = 12163.649 sec
Answer:
Explanation:
Given that
Height of the tree is 3.7m
Therefore yo=3.7m
yox= 0m
The tiger lands 4.8m from the tree
Then, Range x=4.8m
Since she flies horizontally and she lands away from the bottom of the tree, her path will be trajectory as shown in the attachment
Let know the time of flight, using the equation of motion
voy is the initial velocity of the vertical motion of the is the tiger, which is zero at the beginning.
y = y0 + voy*t + ½*g*t²
Given that,
y=3.7m
yo=0m
voy=0m/s
g=9.81m/s²
y = y0 + voy*t + ½*g*t²
3.7=0+0•t+½×9.81×t²
3.7=0+0+4.905t²
3.7=4.905t²
t²=3.7/4.905
t²=0.7543
t=√0.7543
t=0.87sec
Time to reach the ground is
Now to know the initial velocity of the horizontal motion, using equation of motion
x=xo+Voxt
Vox is the horizontal initial velocity of the tiger.
x=xo+Voxt
4.8=0+Vox×0.87
4.8=0+0.87Vox.
4.8=0.87Vox.
Then, Vox=4.8/0.87
Vox=5.52m/s
Then, her initial velocity Vo
Vo=√voy²+vox²
Vo=√0²+5.52²
Vo=√5.52²
Vo=5.52m/s
The initial velocity is 5.52m/s
Answer:
Look at explanation
Explanation:
a) Kinetic Friction= μmg
μmg=0.53*88.9*9.8=461.75N
b) -461.75N=ma
a= -5.19m/s^2
v=v0+at
5.19*1.7=v0
v0=8.81m/s^2
Answer:
Well your answer is peed not velocity because there is no direction
speed=0.086666666666667 m/s
Explanation:
Speed = distance/ time
7.8 m/ 90s
speed=0.086666666666667 m/s