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Vaselesa [24]
3 years ago
7

starting from a stop a traffic signal, a car speeds up to 20 m/s in 5 seconds. calculate the acceleration of the car.

Physics
1 answer:
Ira Lisetskai [31]3 years ago
8 0

Answer:

5.867 m/s^2

Explanation:

Initial Speed > 0 m/s

Final Speed > 20 m/s

Time > 5 sec.

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The answer is 2500 newtons. F = M * A, so 500 kg x 5 m/s = 2500 newtons.
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Where does wave reflection occur?
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Wave reflection occurs when waves reflect or rebound off of a surface. This is like an echo because the sound waves are reflected from a distant surface 
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A boat heads north in still water at 4.5 m/s directly across a river that is running east at 3.0 m/s. What is the velocity of th
Fynjy0 [20]
<h2>Velocity of the boat with respect to Earth is 5 m/s 56.31° north of east</h2>

Explanation:

A boat heads north in still water at 4.5 m/s directly across a river that is running east at 3.0 m/s.

Let north be positive y axis and east be positive x axis.

We have

         Velocity of boat = 4.5 j m/s

          Velocity of river = 3 i m/s

Velocity of the boat with respect to Earth = 3 i + 4.5 j

\texttt{Magnitude of velocity = }\sqrt{3^2+4.5^2}\\\\\texttt{Magnitude of velocity = }5.41m/s

\texttt{Angle = }tan^{-1}\left ( \frac{4.5}{3}\right )\\\\\texttt{Angle = }56.31^0

That is 56.31° north of east.

Velocity of the boat with respect to Earth is 5 m/s 56.31° north of east

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2 years ago
A particle with a positive charge q is moving in the positive x direction with velocity of magnitude v0. If there were an electr
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Answer:

First, let's define the coordinate axes: positive x direction is to the right, positive y direction is to upwards, and z direction is out-of-the plane (towards you).

If the particle is moving with velocity v_0 in the presence of an external E-field, than according to the below formula E-field pushes the positive charge in the direction of the field, which is upward.

F = Eq.

If the velocity of the particle is unchanged, this means that the particle does not have an acceleration, so net force applied to the particle is zero.

We know that the force caused by the E-field is upwards, so an equal amount of another force is directed downwards. This second force is caused by magnetic field. |F_B| = qvB

F_{net} = 0\\F_{net} = F_E - F_B\\0 = qE_0 - qvB\\qE_0 = qvB\\B = \frac{E_0}{v}

This is the magnitude of the magnetic field.

For the direction of the magnetic field we can use right-hand rule with the following equation:

F_B = q(v \times B)

Here, v is in the x-direction. F_B is in the (-y)-direction.

According to the right-hand rule, B-field should be in the z-direction (out-of-the plane, towards you.)

Explanation:

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3 years ago
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