Answer:
A. moving forward for 10m at a steady pace of 2m/s
B. moving backwards 8m at a steady pace of 2.67m/s
C. staying in the same spot for 4 seconds
D. moving 9m at a steady pace of 4.5m/s
E. moving 4.5m with an <u><em>average</em></u><em> </em>pace of 1.5m/s
Answer:
Matrix multiplication is not conmutative
Step-by-step explanation:
The matrix multiplication can be performed if the number of columns of the first matrix is equal to the number of rows of the second matrix
Let A with dimension mxn and B with dimension nxp represent two matrix
The multiplication of A by B is a matrix C with dimension mxp, but the multiplication of B by A is can't be calculated because the number of columns of B is not the number of rows of A. Therefore, you can notice that is not conmutative in general.
But even if the multiplication of AB and BA is defined (For example if A and B are squared matrix of 2x2) the multiplication is not necessary conmutative.
The matrix multiplication result is a matrix which entries are given by dot product of the corresponding row of the first matrix and the corresponding column of the second matrix:
![A=\left[\begin{array}{ccc}a11&a12\\a21&a22\end{array}\right]\\B= \left[\begin{array}{ccc}b11&b12\\b21&b22\end{array}\right]\\AB = \left[\begin{array}{ccc}a11b11+a12b21&a11b12+a12b22\\a21b11+a22b21&a21b12+a22b22\end{array}\right]\\\\BA=\left[\begin{array}{ccc}b11a11+b12a21&b11a12+b12a22\\b21a11+b22ba21&b21a12+b22a22\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da11%26a12%5C%5Ca21%26a22%5Cend%7Barray%7D%5Cright%5D%5C%5CB%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Db11%26b12%5C%5Cb21%26b22%5Cend%7Barray%7D%5Cright%5D%5C%5CAB%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da11b11%2Ba12b21%26a11b12%2Ba12b22%5C%5Ca21b11%2Ba22b21%26a21b12%2Ba22b22%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5CBA%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Db11a11%2Bb12a21%26b11a12%2Bb12a22%5C%5Cb21a11%2Bb22ba21%26b21a12%2Bb22a22%5Cend%7Barray%7D%5Cright%5D)
Notice that in general, the result is not the same. It could be the same for very specific values of the elements of each matrix.
The two numbers that have a product of 48 are 6 and 8 or 12 and 4, etc. They can be multiplied together to get 48, which is the product of the two numbers.
The formula for finding the product of two numbers is to multiply them together. For example, if you have two numbers, a and b, the product of these two numbers is a multiplied by b or an a x b.
The two numbers that have a product of 48 and a sum of 16 are 4 and 12. You can multiply 4 and 12 together to get 48, and you can add them together to get 16.
When the product of two numbers is one of each number, the other number is 1. This means that when the product of two numbers is the same as one of the numbers, the other number must be 1, as 1 multiplied by any number is always equal to itself.
Learn more about the product of two numbers with an example:
brainly.com/question/27860917
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Answer:
It will take them 5 hours to meet if they start moving towards eachother simultaneusly.
Step-by-step explanation:
Distance, s = 540 miles
Motocycle's speed, v = 48 mph
Time for motorcycle to cover 48 miles, t = 
=
= 11.25 h
For a car it takes 2.25 hours less than 11.25 for motorcycle:
Time for car than becomes: 11.25 - 2.25 = 9 h
Speed for car would be v(c) = 
=
= 60 mph
<em>For finding when they will meet, we will need relative speed: </em>
Since they are moving towards each other the relative speed is the sum of speed of car and the speed of motorcycle
Relative Speed = 48 + 60 = 108 mph
Distance = 540 miles
Time = 
= 
= 5 hours