All categories

3 years ago

The mean of 10 numbers is 9, then the sum (total) of these numbers will be

Engineering

2 answers:

Triss [41]3 years ago

6 0

Answer:

Explanation:

mean=sum÷number

sum=number×mean

sum=10×9

sum=90

qwelly [4]3 years ago

5 0

Answer:

Explanation:

mean is basically taking the sum of all numbers and then dividing the sum with the number of all given numbers..

here, the mean is 9, total numbers are 10.. so the sum will be 9 multiplied by 10, that is 90.

You might be interested in

Evaluate (√31-4√21)

nika2105 [10]

Answer:

-12.76253842

Explanation:

4 0

3 years ago

g A food department is kept at -12oC by a refrigerator in an environment at 30oC. The total heat gain to the food department is

boyakko [2]

Answer:

a) $\dot W = 0.417\,kW$ , b) $COP_{R} = 2.198$ , c) Irreversible.

Explanation:

a) The power input required by the refrigerator is:

$\dot W = \dot Q_{H} - \dot Q_{L}$

$\dot W = \left(4800\,\frac{kJ}{h} - 3300\,\frac{kJ}{h}\right)\cdot \left(\frac{1}{3600} \,\frac{h}{s} \right)$

$\dot W = 0.417\,kW$

b) The Coefficient of Performance of the refrigerator is:

$COP_{R} = \frac{\dot Q_{L}}{\dot W}$

$COP_{R} = \frac{3300\,\frac{kJ}{h} }{(0.417\,kW)\cdot \left(3600\,\frac{s}{h} \right)}$

$COP_{R} = 2.198$

c) The maximum ideal Coefficient of Performance of the refrigeration is given by the inverse Carnot's Cycle:

$COP_{R,ideal} = \frac{T_{L}}{T_{H}-T_{L}}$

$COP_{R,ideal} = \frac{261.15\,K}{303.15\,K - 261.15\,K}$

$COP_{R,ideal} = 6.218$

The refrigeration cycle is irreversible, as $COP_{R} < COP_{R,ideal}$ .

3 0

3 years ago

Tool life testing on a lathe under dry cutting conditions gauge 'n' and 'C' of Taylor tool life equation as 0.12 and 130 m/min.

Tom [10]

Answer:

So % increment in tool life is equal to 4640 %.

Explanation:

Initially n=0.12 ,V=130 m/min

Finally C increased by 10% , V=90 m/min

Let's take the tool life initial condition is $T_1$ and when C is increased it become $T_2$ .

As we know that tool life equation for tool

$VT^n=C$

At initial condition $130\times (T_1)^{0.12}=C$ ------(1)

At final condition $90\times (T_2)^{0.12}=1.1C$ -----(2)

From above equation

$\dfrac{130\times (T_1)^{0.12}}{90\times (T_2)^{0.12}}=\dfrac{1}{1.1}$

$T_2=47.4T_1$

So increment in tool life = $\dfrac{T_2-T_1}{T_1}$

= $\dfrac{47.4T_1-T_1}{T_1}$

So % increment in tool life is equal to 4640 %.

7 0

3 years ago

Joe is a chemical engineer whose plant discharges heavy metals into the local river. By the test authorized by the city governme

chubhunter [2.5K]

Answer:

B probably

Explanation:

Because the prompt doesn't specify what sort of violation it could be anything maybe when they release the metals during the day and so on.

5 0

2 years ago

Compression is generally lost in 3 places

natima [27]

Answer:

leak in cylinder head, piston holes, bad valves.

Explanation:

4 0

3 years ago

The mean of 10 numbers is 9, then the sum (total) of these numbers will be​

The mean of 10 numbers is 9, then the sum (total) of these numbers will be