Where are the statements then bbs lol
Explanation:
Sum of forces in the x direction:
∑Fx = ma
Rx − 250 N = 0
Rx = 250 N
Sum of forces in the y direction:
∑Fy = ma
Ry − 120 N − 300 N = 0
Ry = 420 N
Sum of forces in the z direction:
∑Fz = ma
Rz − 50 N = 0
Rz = 50 N
Sum of moments about the x axis:
∑τx = Iα
Mx + (-50 N)(0.2 m) + (-120 N)(0.1 m) = 0
Mx = 22 Nm
Sum of moments about the y axis:
∑τy = Iα
My = 0 Nm
Sum of moments about the z axis:
∑τz = Iα
Mz + (250 N)(0.2 m) + (-120 N)(0.16 m) = 0
Mz = -30.8 Nm
Answer:
QPSK: 7.5 MHz
64-QAM:2.5 MHz
64-Walsh-Hadamard: 160 MHz
Explanation:
See attached picture.
Answer:
#Initialise a tuple
team_names = ('Rockets','Raptors','Warriors','Celtics')
print(team_names[0])
print(team_names[1])
print(team_names[2])
print(team_names[3])
Explanation:
The Python code illustrates or printed out the tuple team names at the end of a season.
The code displayed is a function that will display these teams as an output from the program.
Answer:
k = 4.21 * 10⁻³(L/(mol.s))
Explanation:
We know that
k = Ae
------------------- euqation (1)
K= rate constant;
A = frequency factor = 4.36 10^11 M⁻¹s⁻¹;
E = activation energy = 93.1kJ/mol;
R= ideal gas constant = 8.314 J/mol.K;
T= temperature = 332 K;
Put values in equation 1.
k = 4.36*10¹¹(M⁻¹s⁻¹)e![^{[(-93.1*10^3)(J/mol)]/[(8.314)(J/mol.K)(332K)}](https://tex.z-dn.net/?f=%5E%7B%5B%28-93.1%2A10%5E3%29%28J%2Fmol%29%5D%2F%5B%288.314%29%28J%2Fmol.K%29%28332K%29%7D)
k = 4.2154 * 10⁻³(M⁻¹s⁻¹)
here M =mol/L
k = 4.21 * 10⁻³((mol/L)⁻¹s⁻¹)
or
k = 4.21 * 10⁻³((L/mol)s⁻¹)
or
k = 4.21 * 10⁻³(L/(mol.s))
