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2 years ago

How can you contribute to achieved the mission of NSTP during pandemic in your society?

1 answer:

7 0

Answer:

As a member of the youth, I am given the opportunity to advance the mission of NSTP in my society, especially in this time of the pandemic. My civic duty to my society can be fulfilled through sincerely upholding the values of NSTP and applying its principles for the development of the society.

During this time of the pandemic, it is easy to be fearful and anxious that these make us forget to do our part. In my community we have had many activities to help those who are in need. To achieve the mission of NSTP, I will make sure that I will wholeheartedly participate in many of these activities.

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Can be used to eliminate rubbing friction of wheel touching frame. 1.Traction 2.Thrust washer

Vilka [71]

Answer:

thrust washer

can be used to eliminate rubbing friction of wheel touching frame

5 0

2 years ago

When CO2 rises, temperature rises. Why do you think this is?

icang [17]

Answer:

The warming causes the oceans to release CO2. The CO2 amplifies the warming and mixes through the atmosphere, spreading warming throughout the planet. So CO2 causes warming AND rising temperature causes CO2 rise. Overall, about 90% of the global warming occurs after the CO2 increase.

Explanation:

6 0

2 years ago

A person holds her hand out of an open car window while the car drives through still air at 65 mph. Under standard atmospheric c

Paraphin [41]

Answer:

$10.8\ \text{lb/ft^2}$

$101.96\ \text{lb/ft}^2$

Explanation:

$v_1$ = Velocity of car = 65 mph = $65\times \dfrac{5280}{3600}=95.33\ \text{ft/s}$

$\rho$ = Density of air = $0.00237\ \text{slug/ft}^3$

$v_2=0$

$P_1=0$

$h_1=h_2$

From Bernoulli's law we have

$P_1+\dfrac{1}{2}\rho v_1^2+h_1=P_2+\dfrac{1}{2}\rho v_2^2+h_2\\\Rightarrow P_2=\dfrac{1}{2}\rho v_1^2\\\Rightarrow P_2=\dfrac{1}{2}\times 0.00237\times 95.33^2\\\Rightarrow P_2=10.8\ \text{lb/ft^2}$

The maximum pressure on the girl's hand is $10.8\ \text{lb/ft^2}$

Now $v_1$ = 200 mph = $200\times \dfrac{5280}{3600}=293.33\ \text{ft/s}$

$P_2=\dfrac{1}{2}\rho v_1^2\\\Rightarrow P_2=\dfrac{1}{2}\times 0.00237\times 293.33^2\\\Rightarrow P_2=101.96\ \text{lb/ft}^2$

The maximum pressure on the girl's hand is $101.96\ \text{lb/ft}^2$

5 0

2 years ago

A spacecraft at rest has moment of inertia of 100 kg-m^2 about an axis of interest. If a 1 newton thruster with a 1 meter moment

Kazeer [188]

To solve this problem we will apply the concepts related to translational torque, angular torque and the kinematic equations of angular movement with which we will find the angular displacement of the system.

Translational torque can be defined as,

$\tau = Fd$

Here,

F = Force

d = Distance which the force is applied

$\tau = (1N)(1m)$

$\tau = 1N\cdot m$

At the same time the angular torque is defined as the product between the moment of inertia and the angular acceleration, so using the previous value of the found torque, and with the moment of inertia given by the statement, we would have that the angular acceleration is

$\tau = I\alpha$

$\alpha = \frac{\tau}{I}$

$\alpha = \frac{1N\cdot m}{100kg\cdot m^2}$

$\alpha = 0.01rad/s^2$

Now the angular displacement is

$\theta = \omega_0 t + \frac{1}{2}\alpha t^2$

Here

$\omega_0$ = Initial angular velocity

t = time

$\alpha =$ Angular acceleration

$\theta$ = Angular displacement

Time is given as 1 minute, in seconds will be

$t = 1m = 60s$

There is not initial angular velocity, then

$\theta= \frac{1}{2}\alpha t^2$

Replacing,

$\theta= \frac{1}{2}(0.01)(60)^2$

$\theta = 18rad$

The question neglects the effect of gravitational force.

4 0

3 years ago

sergejj [24]

Answer:

CDI= 1.393 × 10^-3 mg/kg.d

Explanation:

The solution and complete explanation for the above question and mentioned conditions is given below in the attached document.i hope my explanation will help you in understanding this particular question.

8 0

3 years ago