14. The top plate of the bearing partition

EJERCICIO 6

Ket [755]

Answer:

mnfokfnfi3or

Explanation:

can you translate it into english.....

8 0

3 years ago

Q1) Determine the force in each member of the

Sever21 [200]

Answer:

CD = DE = DF = 0
BC = CE = 15 N tension
FA = 15 N compression
CF = 15√2 N compression
BF = 25 N tension
BG = 55/2 N tension
AB = (25√5)/2 N compression

Explanation:

The only vertical force that can be applied at joint D is that of link CD. Since joint D is stationary, there must be no vertical force. Hence the force in link CD must be zero, as must the force in link DE.

At joint E, the only horizontal force is that applied by link EF, so it, too, must be zero.

Then link CE has 15 N tension.

The downward force in CE must be balanced by an upward force in CF. Of that force, only 1/√2 of it will be vertical, so the force in CF is a compression of 15√2 N.

In order for the horizontal forces at C to be balanced the 15 N horizontal compression in CF must be balanced by a 15 N tension in BC.

At joint F, the 15 N horizontal compression in CF must be balanced by a 15 N compression in FA. CF contributes a downward force of 15 N at joint F. Together with the external load of 10 N, the total downward force at F is 25 N. Then the tension in BF must be 25 N to balance that.

At joint B, the 25 N downward vertical force in BF must be balanced by the vertical component of the compressive force in AB. That component is 2/√5 of the total force in AB, which must be a compression of 25√5/2 N.

The <em>horizontal</em> forces at joint B include the 15 N tension in BC and the 25/2 N compression in AB. These are balanced by a (25/2+15) N = 55/2 N tension in BG.

In summary, the link forces are ...

(25√5)/2 N compression in AB
15 N tension in BC
25 N tension in BF
0 N in CD, DE, and EF
15 N tension in CE
15√2 compression in CF
15 N compression in FA

_____

Note that the forces at the pins of G and A are in accordance with those that give a net torque about those point of 0, serving as a check on the above calculations.

8 0

3 years ago

A driver traveling in her 16-foot SUV at the speed limit of 30 mph was arrested for running a red light at 15th and Main, an int

Lynna [10]

Answer:

(a) Yes

(b) 102.8 ft

Explanation:

(a)First let convert mile per hour to feet per second

30 mph = 30 * 5280 / 3600 = 44 ft/s

The time it takes for this driver to decelerate comfortably to 0 speed is

t = v / a = 44 / 10 = 4.4 (s)

given that it also takes 1.5 seconds for the driver reaction, the total time she would need is 5.9 seconds. Therefore, if the yellow light was on for 4 seconds, that's not enough time and the dilemma zone would exist.

(b) At this rate the distance covered by the driver is

$s = v_0t + \frac{at^2}{2}$

$s =44*1.5 + 44(4.4) - \frac{10*4.4^2}{2} = 162.8 (ft)$

Since the intersection is only 60 feet wide, the dilemma zone must be

162.8 - 60 = 102.8 ft

4 0

3 years ago

Consider a system whose temperature is 18°C. Express this temperature in R, K, and °F.

zvonat [6]

Answer:

In Rankine 524.07°R

In kelvin 291 K

In Fahrenheit 64.4°F

Explanation:

We have given temperature 18°C

We have to convert this into Rankine R

From Celsius to Rankine we know that $T(R)=(T_{C}+273.15)\frac{9}{5}$

We have to convert 18°C

So $T(R)=(18+273.15)\frac{9}{5}=524.07^{\circ}R$

Conversion from Celsius to kelvin

$T(K)=(T_{C}+273)$

We have to convert 18°C

$T(K)=(18+273)=291K$

Conversion of Celsius to Fahrenheit

$T(F)=T_{C}\times \frac{9}{5}+32=64.4^{\circ}F$

7 0

3 years ago

What does carbon addition to iron do, what does it produce, how does it change properties, what are its reflections? Describe in

NISA [10]

Answer:

Demire karbon ilavesi ne yapar, ne değiştirir, özellikleri nasıl değiştirir, yansımaları nelerdir? Grafiklerde kullanarak detaylı olarak açıklayın. HMK brainly.com/app/profile/7139574 takip et!!!!

8 0

3 years ago