Answer:
![E[R]](https://tex.z-dn.net/?f=E%5BR%5D)
= 99 Ω
= 2.3094 Ω
P(98<R<102) = 0.5696
Step-by-step explanation:
The mean resistance is the average of edge values of interval.
Hence,
The mean resistance, ![E[R] = \frac{a+b}{2} = \frac{95+103}{2} = \frac{198}{2}](https://tex.z-dn.net/?f=E%5BR%5D%20%3D%20%5Cfrac%7Ba%2Bb%7D%7B2%7D%20%20%3D%20%5Cfrac%7B95%2B103%7D%7B2%7D%20%3D%20%5Cfrac%7B198%7D%7B2%7D)
= 99 Ω
To find the standard deviation of resistance, we need to find variance first.
Hence,
The standard deviation of resistance, 
= 2.3094 Ω
To calculate the probability that resistance is between 98 Ω and 102 Ω, we need to find Normal Distributions.
From the Z-table, P(98<R<102) = 0.9032 - 0.3336 = 0.5696
Answer:
Step-by-step explanation:
S+J+M=36
J=S-2 or J=x-2
M=S-16 or M=x-16
All angles on a triangle add up to 180. If it's a right triangle it would be set up like this: 90+3x-4=6x-5=180. You would subtract 90 from 180 and get 90 left. 3x-4+6x-5=90. Then you would add 5 and 4 to 90.....3x+6x=99. Then you add 3x and 6x then you would be left with 9x=99. Divide 99 by 9 and you get x=11.
42 can be
1 x 42, or
2 x 21, or
3 x 14, or
6 x 7 .
