Assume that the length of the rectangle is "l" and that the width is "w".
We are given that:
(1) The length is one more than twice the base. This means that:
l = 2w + 1 .......> equation I
(2) The perimeter is 92 cm. This means that:
92 = 2(l+w) ...........> equation II
Substitute with equation I in equation II to get the width as follows:
92 = 2(l+w)
92 = 2(2w+1+w)
92/2 = 3w + 1
46 = 3w + 1
3w = 46-1 = 45
w = 45/3
w = 15
Substitute with w in equation I to get the length as follows:
l = 2w + 1
l = 2(15) + 1
l = 30 + 1 = 31
Based on the above calculations:
length of base = 31 cm
width of base = 15 cm
QUESTION 33
The length of the legs of the right triangle are given as,
6 centimeters and 8 centimeters.
The length of the hypotenuse can be found using the Pythagoras Theorem.





Answer: C
QUESTION 34
The triangle has a hypotenuse of length, 55 inches and a leg of 33 inches.
The length of the other leg can be found using the Pythagoras Theorem,





Answer:B
QUESTION 35.
We want to find the distance between,
(2,-1) and (-1,3).
Recall the distance formula,

Substitute the values to get,





Answer: 5 units.
QUESTION 36
We want to find the distance between,
(2,2) and (-3,-3).
We use the distance formula again,





Answer: D
Answer: Use a compass to measure the length of AB. Draw an arc from point B (or point A) with that distance. Extend line AB through that arc and label the intersection as point C. AC is twice the length of AB.
Answer:
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Step-by-step explanation: