Graph C is the correct option.
If you drew a straight line (mostly) connecting the points, it would be linear. A relationship is linear if one variable, in this case, x, increases by approximately the same rate as the other variables, in this case y.
If you drew lines connecting points on the other graphs, they wouldn’t resemble a straight line, therefore, they aren’t linear.
Answer:
the no of puppets that could be made with his string is 21
Step-by-step explanation:
Given that
There is 7 yards
And, it needs one -third of string for each of his puppets
= 7 × 3
= 21 puppets
We simply multiply the 7 yards with the 3 so that the no of puppets could come
hence, the no of puppets that could be made with his string is 21
Answer:
Step-by-step explanation:
![\sqrt{5} \times \sqrt{10} \\ = \sqrt{5} \times \sqrt[]{5} \times \sqrt{2} \\ = 5\sqrt{2}](https://tex.z-dn.net/?f=%20%5Csqrt%7B5%7D%20%20%5Ctimes%20%20%5Csqrt%7B10%7D%20%20%5C%5C%20%20%3D%20%20%5Csqrt%7B5%7D%20%20%5Ctimes%20%20%5Csqrt%5B%5D%7B5%7D%20%20%5Ctimes%20%20%5Csqrt%7B2%7D%20%20%5C%5C%20%20%20%3D%205%5Csqrt%7B2%7D%20)
<h3>Hope it is helpful....</h3>
4t=r
a=pir^2
sub 4t for r
a=pi(4t)^2
a=pi16t^2
a(t)=16pi(t^2)
A. a(t)=16pi(t^2)
B. sub 4 for t
a(4)=16pi4^2
a(4)=16pi16
a(4)=16*16*3.14
a(4)=803.84 square units
A. a(t)=16pi(t^2)
B. 803.84 square units
