$Suppose~that~the~two~numbers~are~x~and~y.\\According~to~question,\\Sum~of~the~numbers = 13\\or, x+y=13........(1)\\or, y = 13-x.......(2)\\Again,\\Sum~of~their~squares=89\\or, x^2+y^2=89\\or, (x+y)^2-2xy=89\\From~eq^n(1)~and~(2),\\13^2-2x(13-x)=89\\or, 169-26x+2x^2=89\\or, 2x^2-26x+169-89=0\\or, 2x^2-26x+80=0\\or, x^2-13x+40=0\\or, x^2-8x-5x+40=0\\or, x(x-8)-5(x-8)=0\\or, (x-5)(x-8)=0\\i.e. x=5~or~8\\When~x=5,~y=13-x=13-5=8\\When~x=8,~y=13-x=13-8=5\\So,~the~two~numbers~are~5~and~8.$

8 0

3 years ago

Line segment AB has endpoints A (-4, 4) and B (2, 4). What is the length of line segment AB?

sineoko [7]

Step-by-step explanation:

the distance is sqrt ( (-6)^2 + (-12)^2) = sqrt( 36 + 144) = sqrt( 180) = sqrt(36*5) = 6 * sqrt(5)

2/(2+4) = 2/6 = 1/3

-2 + (1/3)*6*sqrt(5) = -2 + 2* sqrt(5)

6 + (1/3)*6*sqrt(5) = 6 + 2* sqrt(5)

8 0

3 years ago