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2 years ago

Determine whether or not the triangle with the given side lengths is a right triangle.

1 answer:

8 0

I would say no because I think the highest corner degree would be 79 degrees and a right triangle needs to be 90 degrees. Sorry if it’s wrong.

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Chris earns $10.00 each time he washes his neighbor’s car. The expression 10x represents Chris' earnings. What does the variable

Sholpan [36]

The variable represents the number of times Chris washes the car.

6 0

3 years ago

Read 2 more answers

Consider a sampling distribution with p equals 0.12 and samples of size n each. Using the appropriate formulas, find the mean a

Mandarinka [93]

<h2>Answer with explanation:</h2>

Consider a sampling distribution with p equals 0.12 and samples of size n each.

Then, formula for mean = p

Formula for standard deviation= $\sqrt{\dfrac{p(1-p)}{n}}$

(a) For a random sample of size n equals 5000.

Mean = 0.12

Standard deviation= $\sqrt{\dfrac{0.12(1-0.12)}{5000}}$

$\\\\0.00459565011723\approx0.0046$

(b) For a random sample of size n equals 1000.

Mean = 0.12

Standard deviation= $\sqrt{\dfrac{0.12(1-0.12)}{1000}}$

$\\\\=0.0102761860629\approx0.0103$

(c) For a random sample of size n equals 500.

Mean = 0.12

Standard deviation= $\sqrt{\dfrac{0.12(1-0.12)}{500}}$

$\\\\=0.0145327216997\approx0.0145$

8 0

2 years ago

which statements are true about the graph of the function f(x) = 6x – 4 x2? check all that apply. the vertex form of the functio

Brut [27]

Answer:

The vertex of the function is the point $(-3,-13)$

The graph increase over the interval--------> (-3,∞)

Step-by-step explanation:

we have

$f(x)=6x-4+x^{2}$

1) Convert to vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)+4=x^{2}+6x$

Complete the square. Remember to balance the equation by adding the same constants to each side

$f(x)+4+9=x^{2}+6x+9$

$f(x)+13=x^{2}+6x+9$

Rewrite as perfect squares

$f(x)+13=(x+3)^{2}$

$f(x)=(x+3)^{2}-13$ -----> function in vertex form

2) Find the vertex

The vertex of the function is the point $(-3,-13)$

3) Find the axis of symmetry

we know that

In a vertical parabola, the axis of symmetry is equal to the x-coordinate of the vertex

The x-coordinate of the vertex in this problem is equal to $x=-3$

therefore

the equation of the axis of symmetry is $x=-3$

4) Find the increase-decrease intervals

The graph increase over the interval--------> (-3,∞)

The graph decrease over the interval--------> (-∞,-3)

see the attached figure to better understand the problem

5) Find the x-intercepts of the function

we know that

the x-intercepts are the values of x when the value of the function is equal to zero

In this problem the x-intercepts are

$(-6.61,0)$ and $(0.61,0)$

The function cross the x-axis twice

see the attached figure

5 0

3 years ago

Read 2 more answers

Help with this one because I do not know how to do perpendicular plz put explanation with steps worth 50!

Yuri [45]

Answer:

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line $2x-3y=12$ is $3x+2y=34$

Step-by-step explanation:

Given:

$2x-3y=12$

To Find:

Equation of line passing through ( 16, -7) and is perpendicular to the line

$2x-3y=12$

Solution:

$2x-3y=12$ ...........Given

$\therefore y=\dfrac{2}{3}\times x-4$

Comparing with,

$y=mx+c$

Where m =slope

We get

$Slope = m1 = \dfrac{2}{3}$

We know that for Perpendicular lines have product slopes = -1.

$m1\times m2=-1$

Substituting m1 we get m2 as

$\dfrac{2}{3}\times m2=-1\\\\m2=-\dfrac{3}{2}$

Therefore the slope of the required line passing through (16 , -7) will have the slope,

$m2=-\dfrac{3}{2}$

Now the equation of line in slope point form given by

$(y-y_{1})=m(x-x_{1})$

Substituting the point (16 , -7) and slope m2 we will get the required equation of the line,

$(y-(-7))=-\dfrac{3}{2}\times (x-16)\\\\2y+14=-3x+48\\3x+2y=34......Equation\ of\ line$

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line $2x-3y=12$ is

$3x+2y=34$

3 0

2 years ago

Find the tangent of angle W.

Natasha_Volkova [10]

Where’s the picture, sugar cube?

4 0

2 years ago