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11111nata11111 [884]
3 years ago
15

A manufacturer of prefabricated homes has decided to subcontract four components of the homes. Several companies are interested

in receiving this business, but none can handle more than one subcontract. The bids made by the companies for the various subcontracts are summarized in the following table. Assuming that all the companies can perform each subcontract equally well, to which company should each subcontract be assigned if the home manufacturer wants to minimize payments to the subcontractors? Assuming that all the companies can perform each subcontract equally well, to which company should each subcontract be assigned if the home manufacturer wants to minimize payments to the subcontractors?
Bids by Companies (in $1000s) for Various Subcontract
Company
Component A B C D
1 185 225 193 207
2 200 190 175 225
3 330 320 315 300
4 375 389 425 445
What is an LP model that matches this?
Mathematics
1 answer:
Xelga [282]3 years ago
4 0

Answer:

Following are the solution to the given question:

Step-by-step explanation:

Let x_{ij}=1 when i is the element itself is allocated to 'j' i_0

Min  

185X_{1A}+225X_{1B} +193X_{1C} +207X_{1D} +200X_{2A} +190X_{2B} +175X_{2C}+225X_{2D}+330X_{3A} +320X_{3B} +315X_{3C}+300X_{3D}+375X_{4A}+389X_{4B}+425X_{4C}+ 445X_{4D}

Subject to:

X_{1A} +X_{1B}+X_{1C}+X_{1D}=1\\\\X_{2A} +X_{2B}+X_{2C}+X_{2D}=1\\\\X_{3A} +X_{3B}+X_{3C}+X_{3D}=1\\\\X_{4A} +X_{4B}+X_{4C}+X_{4D}=1\\\\X_{1A} +X_{2A}+X_{3A}+X_{4A}=1\\\\X_{1B} +X_{2B}+X_{3B}+X_{3B}=1\\\\X_{1C} +X_{2C}+X_{3C}+X_{4C}=1\\\\X_{1D} +X_{2D}+X_{3D}+X_{4D}=1

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The number of employees per department are normally distributed with a population standard deviation of 198 employees and an unk
cricket20 [7]

Answer:

EBM = +-54.126

Step-by-step explanation:

In this question we have confidence interval to be 80%

The formula to solve this is in the attachment.

Bar X = 1460

Z-alpha/2 = 1.282

Sd = standard deviation = 198 employees

n = 22 departments

After we have inserted all values in to the formula we have:

1460 +-(1.282*198/√22)

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The error bounded mean EBM

= +-z-alpha/2 x (sd/√n)

= 1.282 x 198/√22

= 1.282 x 42.22

EBM = +-54.126

6 0
3 years ago
Solve this thing pls<br> <img src="https://tex.z-dn.net/?f=3%5Cleft%28q-7%5Cright%29%3D27" id="TexFormula1" title="3\left(q-7\ri
evablogger [386]

Answer:

  • Solution of equation ( q ) = <u>1</u><u>6</u>

Step-by-step explanation:

In this question we have given an equation that is <u>3 </u><u>(</u><u> </u><u>q </u><u>-</u><u> </u><u>7</u><u> </u><u>)</u><u> </u><u>=</u><u> </u><u>2</u><u>7</u><u> </u>and we have asked to solve this equation that means to find the value of <u> </u><u>q</u><u> </u><u>.</u>

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<u>Step </u><u>2</u><u> </u><u>:</u> Adding 21 on both sides :

\quad \: \longmapsto \:3q -  \cancel{ 21} +  \cancel{21} = 27  +  21

On further calculations we get :

\quad \: \longmapsto \:3q = 48

<u>Step </u><u>3 </u><u>:</u> Dividing by 3 from both sides :

\quad \: \longmapsto \: \frac{ \cancel{3}q}{ \cancel{3}}  =  \cancel {\frac{48}{3} }

On further calculations we get :

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<u>Verifying</u><u> </u><u>:</u><u> </u><u>-</u>

Now we are very our answer by substituting value of q in the given equation . So ,

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  • L.H.S = R.H.S

  • Hence, Verified.

<u>Therefore</u><u>,</u><u> </u><u>our </u><u>solution</u><u> </u><u>is </u><u>correct</u><u> </u><u>.</u>

<h2><u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>
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