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3 years ago

If kootie weighs 500 and gains 98 pounds in 2 days how much does he weigh

Mathematics

1 answer:

bezimeni [28]3 years ago

5 0

598
explanation: 500+98= 598

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Which expression is equivalent to 4(2p+4q)

Alina [70]

Answer:

8p+16q

hope this helps

4x2p=8p

4x4q=16q

4 0

3 years ago

A stick is 6 m long. A rope is 2 times as long as the stick.

weeeeeb [17]

Answer:

Step-by-step explanation:

wouldn't it be 12 meters? is this isn't what you need ill figure it out and edit this

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3 years ago

Consider an ANOVA procedure to compare five population means. In this case, the total number of pairs to be considered in multip

Oliga [24]

Answer:

The right response is "0.0085". A further explanation is given below.

Step-by-step explanation:

Let,

P (across each pair, this same null hypothesis would be wrongly rejected) be "a".

Therefore,

⇒ $P=1-P(no \ time \ rejected)$

⇒ $1-(1-a)^6 =0.05$

⇒ $1-a=0.95^{(\frac{1}{6} )}$

⇒ $a=1-0.95^{(\frac{1}{6} )}$

⇒ $0.0085$

7 0

3 years ago

Suppose 8x + 16 ice cream cones were sold on Saturday and 7x – 9 were sold on Sunday. What is the total number of ice cream cone

soldier1979 [14.2K]

Answer:

15x +7

Step-by-step explanation:

Like terms can be combined.

(8x +16) +(7x -9) = (8x +7x) +(16 -9) = 15x +7

The total number of ice cream cones sold was 15x+7.

4 0

3 years ago

The Rockwell hardness index for steel is determined by pressing a diamond point into the steel and measuring the depth of penetr

anygoal [31]

Answer:

We conclude that the steel has an average hardness index of at least 64.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 64

Sample mean, $\bar{x}$ = 62

Sample size, n = 50

Alpha, α = 0.051

Sample standard deviation, s = 8

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 64\\H_A: \mu < 64$

We use one-tailed(left) z test to perform this hypothesis.

Formula:

$z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$z_{stat} = \displaystyle\frac{62 - 64}{\frac{8}{\sqrt{50}} } = -1.767$

Now, $z_{critical} \text{ at 0.05 level of significance } = -2.33$

Since,

$z_{stat} > z_{critical}$

We fail to reject the null hypothesis and accept the null hypothesis. Thus, we conclude that the steel has an average hardness index of at least 64.

8 0

3 years ago