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ddd [48]
3 years ago
15

Which of the following ordered pairs is not a solution to the equation represented by the graph

Mathematics
1 answer:
givi [52]3 years ago
3 0
I don't know what the ordered pairs are here, but anyone that doesn't end with a three. Example, (1,3) is on the graph. so is (27, 3) y, will always be three:) 
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In the adjoining equilateral triangle PQR , X , Y and Z are the middle points of the sides PQ , QR and RP respectively. Prove th
olasank [31]

Answer:

See Below

Step-by-step explanation:

<u>Statements:</u>                                                        <u>Reasons:</u>

<u />1)\text{ } \Delta PQR\text{ is equilateral}                                        Given

2)\text{ }PQ=QR=RP                                               Definition of Equilateral

3)\text{ } X, Y, Z\text{ are the midpoints of } PQ, QR, RP       Given

4)\text{ } PX=XQ                                                        Definition of Midpoint

5)PQ=PX+XQ                                               Segment Addition

6)\text{ } PQ=2XQ                                                      Substitution

7)\text{ } QY=YR                                                        Definition of Midpoint

8)\text{ }QR=QY+YR                                               Segment Addition

9)\text{ } QR=2QY                                                       Substitution

10)\text{ } 2XQ=2QY                                                  Substitution

11)\text{ } XQ=QY                                                      Division Property of Equality

12)\text{ }  XQ=PX=QY=YR                                Transitive Property

13)\text{ } RZ=ZP                                                       Definition of Midpoint

14)\text{ } RP=RZ+ZP                                             Segment Addition

15)\text{ } RP=2RZ                                                     Substitution

16)\text{ } 2XQ=2RZ                                                   Substitution

17)\text{ } XQ=RZ                                                       Substitution

18)\text{ } XQ=PX=QY=YR=RZ=ZP            Transitive Property

19)\text{ } \angle Q\cong \angle R\cong \angle P                                             Definition of Equilateral

20)\text{ } \Delta XQY\cong \Delta YRQ \cong \Delta ZPX                          SAS Congruence

21)\text{ } XY\cong YZ\cong ZX                                           CPCTC

22)\text{ } \Delta XYZ\text{ is equilateral}                                     Equilateral Triangle Theorem

5 0
3 years ago
Read 2 more answers
Please help me I have no clue what to do
Effectus [21]

Answer: A circle is 360° all the way around; therefore, if you divide an arc's degree measure by 360°, you find the fraction of the circle's circumference that the arc makes up. Then, if you multiply the length all the way around the circle (the circle's circumference) by that fraction, you get the length along the arc.

Step-by-step explanation:

3 0
2 years ago
What is this? k/8-5≥-6
ddd [48]

Answer:

k≥-8

Step-by-step explanation:

4 0
3 years ago
A month subscription to a website costs $10 to join and $15.50 per month. Write an equation in slope-intercept form to represent
just olya [345]

Answer:

y = $15.50x + $10

Step-by-step explanation:

y =mx +b

y = $15.50x + $10

m = cost per months

x= number of months

b = Money to join

y= total cost

3 0
3 years ago
2 (Picture) CONVERGENT AND DIVERGENT SERIES PLEASE HELP!!
Ivanshal [37]

Answer:

This series is divergent

F

Step-by-step explanation:

we are given a series

Firstly, we will find nth term

Numerator:

3, 4, 5,...

so, nth term will be

a_n=n+3

Denominator:

4,5,6,....

so, nth term will be

b_n=n+4

so, we can find it's nth term as

c_n=\frac{n+3}{n+4}

we can use divergent test

\lim_{n \to \infty}  c_n=\lim_{n \to \infty} \frac{n+3}{n+4}

we can divide top and bottom by n

\lim_{n \to \infty}  c_n= \lim_{n \to \infty} \frac{n/n+3/n}{n/n+4/n}

\lim_{n \to \infty}  c_n= \lim_{n \to \infty} \frac{1+3/n}{1+4/n}

now, we can plug n=inf

\lim_{n \to \infty}  c_n= \frac{1+0}{1+0}

\lim_{n \to \infty}  c_n=1

Since, it is non-zero value

so, this series is divergent


8 0
3 years ago
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