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jok3333 [9.3K]
3 years ago
7

What is the length of pQ

Mathematics
1 answer:
garik1379 [7]3 years ago
7 0

Where is the question???

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F(b)-f(a)
luda_lava [24]
Nooooooooooooooooooooooooooooooooooo
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3 years ago
Which ordered pair is the solution to y = 2x + 10?
Eduardwww [97]
The best way to solve a problem like this is guess and check.

y = 2x + 10

2 = 2(2) +10

2 = 4+10
2 = 14 NO

y = 2x + 10

4 = -3(2) +10
4 = -6 +10
4 = 4 YES . . . C is your answer
7 0
3 years ago
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2x+2y=16 , 6x+4y=38 what is the value of x
ra1l [238]
1st equation—x, substitute y: 
<span>3x + 2(x + 3) = 16 </span>
<span>3x + 2x + 6 = 16 </span>
<span>5x = 10 </span>
<span>x = 2 </span>

<span>y in the above equation: </span>
<span>= 2 + 3 </span>
<span>= 5 </span>

<span>Answer: x = 2, y = 5</span>
5 0
3 years ago
10 points! Help please!
liraira [26]

Answer:

74.2899408284 meters

Step-by-step explanation:

2.7 : 1.69

x : 46.5

46.5/1.69=27.5147928994

27.5147928994*2.7=74.2899408284

8 0
3 years ago
What is the radius of a sphere with a volume of 1/6 pie
Yakvenalex [24]

Answer:

\large\boxed{the\ radius\ R=\dfrac{1}{2}}

Step-by-step explanation:

The formula of a volume of a sphere:

V=\dfrac{4}{3}\pi R^3

We have

V=\dfrac{1}{6}\pi

Substitute:

\dfrac{4}{3}\pi R^3=\dfrac{1}{6}\pi        <em>divide both sides by π</em>

\dfrac{4}{3}R^3=\dfrac{1}{6}          <em>multiply both sides by 3</em>

3\!\!\!\!\diagup^1\cdot\dfrac{4}{3\!\!\!\!\diagup_1}R^3=3\!\!\!\!\diagup^1\cdot\dfrac{1}{6\!\!\!\!\diagup_2}

4R^3=\dfrac{1}{2}          <em>divide both sides by 4</em>

R^3=\dfrac{1}{2}:4\\\\R^3=\dfrac{1}{2}\cdot\dfrac{1}{4}\\\\R^3=\dfrac{1}{8}\to R=\sqrt[3]{\dfrac{1}{8}}\\\\R=\dfrac{\sqrt1}{\sqrt8}\\\\R=\dfrac{1}{2}

3 0
3 years ago
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