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3 years ago

Which orbital is the first to fill with electrons in a given principal energy level?

Chemistry

2 answers:

olasank [31]3 years ago

8 0

<h2>Answer:</h2>

<u>The right option is</u><u> (B) S orbital</u>

<h2>Explanation:</h2>

Each orbital can hold two electrons. One spin-up and one spin-down. The first principal energy level contains only an s sublevel; therefore, it can hold a maximum of two electrons.

The order in which the orbitals are filled is given below

1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p, 8s

Mkey [24]3 years ago

5 0

e) both s and p

hope this helps!

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NASA uses radar to track as much space junk as possible, but it's estimated that millions of pieces

gizmo_the_mogwai [7]

D. All of the above

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3 years ago

Draw the best Lewis structure for NH3 by filling in the bonds, lone pairs, and formal charges. (Assign bonds, lone pairs, radica

kiruha [24]

Answer : The Lewis-dot structure of $NH_3$ is shown below.

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is, $NH_3$

As we know that hydrogen has '1' valence electron and nitrogen has '5' valence electrons.

Therefore, the total number of valence electrons in $NH_3$ = 5 + 3(1) = 8

According to Lewis-dot structure, there are 6 number of bonding electrons and 2 number of non-bonding electrons.

Now we have to determine the formal charge for each atom.

Formula for formal charge :

$\text{Formal charge}=\text{Valence electrons}-\text{Non-bonding electrons}-\frac{\text{Bonding electrons}}{2}$

$\text{Formal charge on N}=5-2-\frac{6}{2}=0$

$\text{Formal charge on }H_1=1-0-\frac{2}{2}=0$

$\text{Formal charge on }H_2=1-0-\frac{2}{2}=0$

$\text{Formal charge on }H_3=1-0-\frac{2}{2}=0$

Hence, the Lewis-dot structure of $NH_3$ is shown below.

3 0

3 years ago

An ancient silver coin has a density of 10.49 g/cm3 at 20°C. If you break the coin that weighs 4.001 in half

Wittaler [7]

The density of each half of the coin is 10.49 g/cm3

In science density is defined as the ratio of mass to volume of an object.

Density is an intrinsic property.It is not affect by the amount of substance present.

This implies that each half of the broken coin must have the same density since it it is an inherent property of every silver material.

The density of each part of the coin therefore is 10.49 g/cm3.

Learn more: brainly.com/question/18320053

7 0

2 years ago

43 milliliters of water weighs 43 g. what is the density of the water?

Anastaziya [24]

Answer:

$\rho =1g/mL$

Explanation:

Hello,

In this case, since the density is defined as the ratio between the mass and the volume as shown below:

$\rho =\frac{m}{V}$

We can compute the density of water for the given 43 g that occupy the volume of 43 mL:

$\rho =\frac{43g}{43mL}=1g/mL$

Regards.

4 0

3 years ago

If 3.289 x 10^23 atoms of potassium react with excess water, how many grams of hydrogen gas would be produced?

GarryVolchara [31]

Answer:

The amount in grams of hydrogen gas produced is 0.551 grams

Explanation:

The parameters given are;

Number of atoms of potassium, aₙ = 3.289 × 10²³ atoms

Chemical equation for the reaction is given as follows;

2K + 2H₂O $\rightarrow$ KOH + H₂

Avogadro's number, $N_A$ , regarding the number of molecules or atom per mole is given s follows;

$N_A$ = 6.02 × 10²³ atoms/mole

Therefore;

The number of moles of potassium present = 3.289 × 10²³/(6.02 × 10²³) = 0.546 moles

2 moles of potassium produces one mole of hydrogen gas, therefore;

1 moles of potassium produces 1/2 mole of hydrogen gas, and 0.546 moles of potassium will produce 0.546/2 moles of hydrogen which is 0.273 moles of hydrogen gas

The molar mass of hydrogen gas = 2.016 grams

Therefore, 0.273 moles will have a mass of 0.273×2.016 = 0.551 grams.

The amount in grams of hydrogen gas produced = 0.551 grams.

8 0

3 years ago