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3 years ago

Can someone please explain how to do this i am so confused i just want to pass this class please :(

Mathematics

1 answer:

mash [69]3 years ago

7 0

Answer:

x=6√3

Step-by-step explanation:

In 30-60-90 triangles, if the hypotenuse is x, the longest leg is $\frac{x}{2}$ , and the shortest leg is $\frac{x\sqrt{3} }{2}$ .

If the longest leg is 6, then $\frac{x}{2} =6$

Multiply by 2,

$x=12$

If x=12,

$\frac{12\sqrt{3} }{2}$

$=6\sqrt{3}$

So, the shortest leg is 6√3.

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3 years ago

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borishaifa [10]

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Tanzania [10]

Answer:

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2) 1/2

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2. In first place, Maria spent 13 for the book.

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3 years ago

A spacecraft is traveling with a velocity of v0x = 5320 m/s along the +x direction. Two engines are turned on for a time of 739

OlgaM077 [116]

Answer:

The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction

Step-by-step explanation:

For a constant acceleration: $v_{f}=v_{0}+at$ , where $v_{f}$ is the final velocity in a direction after the acceleration is applied, $v_{0}$ is the initial velocity in that direction before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied.
Then for the x direction it is known that the initial velocity is $v_{0x} =$ 5320 m/s, the acceleration (the applied by the engine) in x direction is $a_{x}$ 1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the is 739 s. Then: $v_{fx}=v_{0x}+a_{x}t=5320\frac{m}{s} +1.79\frac{m}{s^{2} }*739s=6642.81\frac{m}{s}$
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3 years ago