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xxMikexx [17]
3 years ago
15

X2+5xy+6y2 challenge question

Mathematics
1 answer:
saul85 [17]3 years ago
6 0

Answer:

Step-by-step explanation:

x^2+5xy+6y^2\\ \\ x^2+2xy+3xy+6y^2\\ \\ x(x+2y)+3y(x+2y)\\ \\ (x+3y)(x+2y)

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How many of each angles are in a pentagon
Illusion [34]

There are 108 degrees in each interior angle of a regular pentagon .


I hope that's help !

8 0
3 years ago
Read 2 more answers
HELP ME pleaseeeee ill mark you as brainiest if I get two answers
sergiy2304 [10]

                                        Question 9

Given the segment XY with the endpoints X and Y

Given that the ray NM is the segment bisector XY

so

NM divides the segment XY into two equal parts

XM = MY

given

XM = 3x+1

MY = 8x-24

so substituting XM = 3x+1 and MY = 8x-24 in the equation

XM = MY

3x+1 = 8x-24

8x-3x = 1+24

5x = 25

divide both sides by 5

5x/5 = 25/5

x = 5

so the value of x = 5

As the length of the segment XY is:

Length of segment XY = XM + MY

                                = 3x+1 + 8x-24

                                = 11x - 23

substituting x = 5

                               = 11(5) - 23

                               = 55 - 23

                               = 32

Therefore,

The length of the segment = 32 units

                                        Question 10)

Given the segment XY with the endpoints X and Y

Given that the line n is the segment bisector XY

so

The line divides the segment XY into two equal parts at M

XM = MY

given

XM = 5x+8

MY = 9x+12

so substituting XM = 5x+8 and MY = 9x+12 in the equation

XM = MY

5x+8 = 9x+12

9x-5x = 8-12

4x = -4

divide both sides by 4

4x/4 = -4/4

x = -1

so the value of x = -1

As the length of the segment XY is:

Length of segment XY = XM + MY

                                = 5x+8 + 9x+12

                                = 14x + 20

substituting x = 1

                               = 14(-1) + 20

                               = -14+20

                               = 6

Therefore,

The length of the segment XY = 6 units

8 0
3 years ago
Find the 10th term of the geometric sequence whose common ratio is 2/3 and whose first term is 3.
Sergeu [11.5K]

Answer:

\frac{512}{6561}

Step-by-step explanation:

1) if according to the condition a₁=3 and r=2/3, then a₁₀ can be calculated as:

a₁₀=a₁*r⁹;

2) according  to the rule above:

a₁₀=3*(2/3)⁹=512*3/(6561*3)=512/6561.

5 0
2 years ago
the two shorter sides of a triangle are the same length. the length of the longer side is 5 m longer than each of the shorter si
STatiana [176]
Let the length of the shorter sides be x, then
Perimeter = x + x + x + 5
29 = 3x + 5
3x = 29 - 5 = 24
x = 24/3 = 8

Therefore, the length of longest side is 8 + 5 = 13 m.
4 0
3 years ago
Read 2 more answers
Help!! It's question 14
Leona [35]

Answer:

200/120 = 5/3

5/3 x 3 = 5 oz

<u>you can also do it this way:</u>

3/120 = x/200

x = 600/120 = 5

5 0
3 years ago
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