Ask question

Ask question

All categories

3 years ago

13

Will the reaction time significantly affect measurements you might make using instruments for this course? How could you minimiz

e its role?

1 answer:

Kisachek [45]3 years ago

8 0

Answer:

Dndndjddydg

Explanation:

Snshsydyddu

You might be interested in

A car movingin a straight line starts at x = 0 at t = 0. It passes the point x = 25.0 m with a speed of 11.0 m????s at t = 3.00s

makvit [3.9K]

Answer:

Part a)

at t = 3.00 s

$v = 8.33 m/s$

at t = 20.0 s

$v = 19.25 m/s$

Part b)

at t = 3.00 s

$a = 3.67 m/s^2$

at t = 20.0 s

$a = 2.25 m/s^2$

Explanation:

The car starts at x = 0

Part a)

Now at t = 3.00 s

the position of the car is given as x = 25 m and its speed is given as v = 11 m/s

Now for average velocity we have

$v = \frac{displacement}{time}$

$v = \frac{25 - 0}{3}$

$v = 8.33 m/s$

Now for average acceleration we have

$a = \frac{v - 0}{t}$

$a = \frac{11 - 0}{3}$

$a = 3.67 m/s^2$

Part b)

Now at t = 20.0 s

the position of the car is given as x = 385 m and its speed is given as v = 45 m/s

Now for average velocity we have

$v = \frac{displacement}{time}$

$v = \frac{385 - 0}{20}$

$v = 19.25 m/s$

Now for average acceleration we have

$a = \frac{v - 0}{t}$

$a = \frac{45 - 0}{20}$

$a = 2.25 m/s^2$

4 0

3 years ago

Suppose the average mass of each of 20,000 asteroids in the solar system is 1017 kg. Compare the total mass of these asteroids t

blondinia [14]

Answer:

The mass of the asteroids is 0.000334896182184 times the mass of the Earth.

39929.4542466 m

Explanation:

Total mass of the asteroids

$m_a20000\times 10^{17}=2\times 10^{21}\ kg$

$m_e$ = Mass of Earth = $5.972\times 10^{24}\ kg$

The ratio is

$\dfrac{m_a}{m_e}=\dfrac{2\times 10^{21}}{5.972\times 10^{24}}\\\Rightarrow \dfrac{m_a}{m_e}=0.000334896182184$

The mass of the asteroids is 0.000334896182184 times the mass of the Earth.

Volume is given by

$V=\dfrac{m}{\rho}\\\Rightarrow \dfrac{4\pi}{3\times 8} d^3=\dfrac{m}{\rho}\\\Rightarrow d^3=\dfrac{3\times 8}{4\pi}\dfrac{m}{\rho}\\\Rightarrow d=(\dfrac{3\times 8}{4\pi}\dfrac{m}{\rho})^{\dfrac{1}{3}}\\\Rightarrow d=(\dfrac{3\times 8}{4\pi}\dfrac{10^{17}}{3000})^{\dfrac{1}{3}}\\\Rightarrow d=39929.4542466\ m$

The diameter is 39929.4542466 m

6 0

3 years ago

Can anyone please tell me the properties of image formed in a spherical mirror?

notsponge [240]

Answer:

The two rays, CY and DM are diverging rays and when extended behind the mirror, they appear to intersect each other at point M'. Therefore, the properties of the images formed here are formed behind the mirror, between the pole and principal focus (f), the images are diminished and are virtual and erect.

Explanation:

<h2>Spherical Mirrors</h2>

There are two kinds of spherical mirrors, concave and convex.

The focal point (F) of a concave mirror is the point at which a parallel beam of light is "focussed" after reflection in the mirror. ...

The focal length (f) and radius of curvature (R) are defined in the diagram at the right.

<h3>hope it helps and thanks for following </h3><h2>please give brainliest </h2>

6 0

3 years ago

Read 2 more answers

Max is a network technician who just terminated the ends on a new copper cable used between two legacy switches. When he connect

Olegator [25]

Answer:

The cable used is a straight through cable.

Explanation:

The cable used here is a straight through cable, that is why it fails to establish the connection.

Cross-over cables are used to communicate over legacy switch. It is used to connect computing devices directly.

In a cross over cable, signal gets transmit from one end of the device to the other.

7 0

3 years ago

COVA hahtyimghhjlouvr

Kryger [21]

Answer:

heyyy

Explanation:

what's poppin

6 0

3 years ago