Well, first of all, the car is not moving at a uniform velocity, because,
on a curved path, its direction is constantly changing. Its speed may
be constant, but its velocity isn't.
The centripetal force on a mass 'm' that keeps it on a circle with radius 'r' is
F = (mass) · (speed)² / (radius).
For this particular car, the force is
(2,000 kg) · (25 m/s)² / (80 m)
= (2,000 kg) · (625 m²/s²) / (80 m)
= (2,000 · 625 / 80) (kg · m / s²)
= 15,625 newtons .
Answer:
√2µgd = vi
Explanation:
Given that the mass of object is m
Sliding speed of object is vi
coefficient of kinetic friction is µ
Distance covered is d
Final speed, vf is 0
Equation to apply will be;
v²f=v²i-2µgd where g is acceleration due to gravity
v²f+2µgd=v²i----------------------but v²f = 0
2µgd=v²i
√2µgd = vi
may i ask your answer soloutions... and i believe that the correct answer is mass
For the answer to the question above, each horse's force forms a right angle triangle with the barge and subtends an angle of 60/2 = 30°. The resultant in the direction of the barge's motion is:
Fx = Fcos(∅)
We can multiply this by 2 to find the resultant of both horses.
Fx = 2Fcos(∅)
Fx = 2 x 720cos(30)
Fx = 1247 N
Answer:
B. Liquids
Explanation:
Just had this question on my test.
Hope this helps :)
