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Delicious77 [7]
3 years ago
8

What symbol makes the statement true? 4/6 3/8​

Mathematics
2 answers:
soldier1979 [14.2K]3 years ago
7 0

Answer:

>

Step-by-step explanation:

because

16/24 > 9/24 :)

Anastasy [175]3 years ago
5 0
4/6 is 0.666666666666667
3/8 is 0.375
So 4/6>3/8
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Which of the following is the missing reason? Statements Reasons two thirds times x plus 7 equals negative 5 Given 2x 21 = â’15
pentagon [3]

The correct option is B. Distributive property

Given,

\frac{2}{3} x+7=-5\\

On solving the above equation,

multiplying both sides by 3 we, get

2x+21=-15

now subtracting 21 from both the sides,

2x=-36\\

dividing both the sides by 2 we get,

x=-18

Since in the above steps we follow all the giving property except the distributive property.

Hence the correct option is B. Distributive property.

For more details follow the link:

brainly.com/question/13130806

6 0
2 years ago
BRIANLIST ANSWER!! Please help on this one question ( if you’re good at this) thanks :))
ivann1987 [24]

Answer:

Step-by-step explanation:

(21²+10²)½ = 23.25= 23.3

5 0
3 years ago
What is 0.54 converted to a simplified fraction?
nadya68 [22]
0.54=0.54/1=5.4/10=54/100=27/50
4 0
3 years ago
What is 5 divided by 5
Triss [41]

Answer:

1

Step-by-step explanation:

You have 5 jelly beans and 4 imaginary friends

You have to split the jellybeans between yourself and your pretend friends.

Each of you gets 1 jellybean

(Except you get all the jellybeans because your friends don't exist)

Hope this helps :)

6 0
3 years ago
A gambler has a coin which is either fair (equal probability heads or tails) or is biased with a probability of heads equal to 0
yawa3891 [41]

Answer:

(a) 0.1719

(b) 0.3504

Step-by-step explanation:

For every coin the number of heads follows a Binomial distribution and the probability that x of the 10 times are heads is equal to:

P(x)=\frac{n!}{x!(n-x)!}*p^x*(1-p)^{10-x}

Where n is 10 and p is the probability to get head. it means that p is equal to 0.5 for the fair coin and 0.3 for the biased coin

So, for the fair coin, the probability that the number of heads is less than 4 is:

P(x

Where, for example, P(0) and P(1) are calculated as:

P(0)=\frac{10!}{0!(10-0)!}*0.5^0*(1-0.5)^{10-0}=0.0009\\P(1)=\frac{10!}{1!(10-1)!}*0.5^1*(1-0.5)^{10-1}=0.0098

Then, P(x, so there is a probability of 0.1719 that you conclude that the coin is biased given that the coin is fair.

At the same way, for the biased coin, the probability that the number of heads is at least 4 is:

P(x\geq4 )=P(4)+P(5)+P(6)+...+P(10)

Where, for example, P(4) is calculated as:

P(4)=\frac{10!}{4!(10-4)!}*0.3^4*(1-0.3)^{10-4}=0.2001

Then, P(x\geq4 )=0.3504, so there is a probability of 0.3504 that you conclude that the coin is fair given that the coin is biased.

7 0
4 years ago
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