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Rashid [163]
3 years ago
5

Answer please !!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
cricket20 [7]3 years ago
8 0

Answer:

37°

Step-by-step explanation:

ΔOPQ extended trough Q to R

m∠PQR = (7x-19)° -is an exterior angle to the triangle

m∠OPQ = (2x-3)° -angle inside the triangle

m∠QOP = (x+16)° -angle inside the triangle

m∠PQR = ?

m∠PQR = m∠OPQ + m∠QOP

7x-19 = 2x-3 +x+16

7x -2x-x = 16-3+19

4x = 32

x=32/4=8

m∠PQR = 7x-19 = 7*8-19  =56 -19= 37°

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Answer:

<h2>x = 1, y = 1 → (1, 1)</h2>

Step-by-step explanation:

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\bold{SUBSTITUTION\ METHOD}\\\\\left\{\begin{array}{ccc}x+6y=7&\text{subtract}\ 6y\ \text{from both sides}\\5x+8y=13\end{array}\right\\\\\left\{\begin{array}{ccc}x=7-6y&(1)\\5x+8y=13&(2)\end{array}\right\\\\\text{Substitute (1) to (2):}\\\\5(7-6y)+8y=13\qquad\text{use the distributive property}\\(5)(7)+(5)(-6y)+8y=13\\35-30y+8y=13\qquad\text{subtract 35 from both sides}\\-30y+8y=13-35\qquad\text{combine like terms}\\-22y=-22\qquad\text{divide both sides by (-22)}\\\boxed{y=1}

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4 0
3 years ago
Read 2 more answers
The waiters poured 160 eight-ounce glasses of water at the banquet. How many gallons is this? Show your work.
larisa86 [58]
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7 0
3 years ago
This is so important please help
Shtirlitz [24]

Given:

The center of the circle = (-1,0)

Point on the circle = (2,-4).

To find:

The equation of the circle.

Solution:

Distance between two points is

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Distance between the center (-1,0) and the point on the circle (2,-4) is the radius of the circle.

r=\sqrt{(2-(-1))^2+(-4-0)^2}

r=\sqrt{(2+1)^2+(-4)^2}

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On further simplification, we get

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Where, (h,k) is the center and r is the radius of the circle.

The radius of the circle is 5 and the center is at (-1,0), so the equation of the circle is

(x-(-1))^2+(y-0)^2=5^2

(x+1)^2+y^2=25

Therefore, the first option is correct, i.e., (x+1)^2+y^2=25.

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3 years ago
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Arada [10]
F(4)=0 and F(5)= -10
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3 years ago
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