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MrRissso [65]
3 years ago
8

ILL GIVE ANYTHING PLEEEASSE HELLLP

Mathematics
1 answer:
laila [671]3 years ago
5 0
0.020625 I think?!?!
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Find f(-5) and f(12) for each piecewise function f(x){-4x+3 if x<3
Law Incorporation [45]
<h3>Answers:</h3>
  • f(-5) = 23
  • f(12) = 433

==================================================

Explanation:

The given piecewise function is

f(x) = \begin{cases}-4x+3 \ \text{ if } \ x < 3\\-x^3 \ \text{ if } \ 3 \le x \le 8\\3x^2+1 \ \text{ if } \ x > 8\end{cases}

At first piecewise functions may be strange confusing things, but they aren't so bad. I like to think of it like this: f(x) is a function that changes its identity based on what the input x is. We have three situations

  • f(x) = -4x+3 when x < 3
  • f(x) = -x^3 when 3 \le x \le 8
  • f(x) = 3x^2+1 when x > 8

In a sense, we have three different functions but they are combined somehow.

If x is smaller than 3, then we go for the first definition. Or if x is between 3 and 8, then we go for the second definition. Or if x is larger than 8, then we go for the third definition.

-----------------------

f(-5) means f(x) when x = -5. We see that -5 is smaller than 3, so x = -5 makes x < 3 true. We'll use the first definition

f(x) = -4x+3

f(-5) = -4(-5)+3

f(-5) = 20+3

f(-5) = 23

------------------------

Now the input is x = 12. This is larger than 8. In other words, x = 12 makes x > 8 true. We'll use the third definition

f(x) = 3x^2+1

f(12) = 3(12)^2+1

f(12) = 3(144)+1

f(12) = 432+1

f(12) = 433

------------------------

Side notes:

  • We won't use the second definition since we don't have any x inputs between 3 and 8
  • To say "less than or equal to" on a keyboard, you can write "<=" without quotes. For example, x \le 5 is the same as x<=5
3 0
4 years ago
What’s the 16th term?
kramer

Put 16 where n is, then do the arithmetic.

... a(16) = -6 + 3(16 -1)

... a(16) = -6 + 45

... a(16) = 39

8 0
4 years ago
Read 2 more answers
HELP!!! URGENT!!! I WILL GIVE BRAINLEIST THING ​
lisov135 [29]

Answer:

Horizontal distance = 0 m and 6 m

Step-by-step explanation:

Height of a rider in a roller coaster has been defined by the equation,

y = \frac{1}{3}x^{2}-2x+8

Here x = rider's horizontal distance from the start of the ride

i). y=\frac{1}{3}x^{2}-2x+8

      =\frac{1}{3}(x^{2}-6x+24)

      =\frac{1}{3}[x^{2}-2(3x)+9-9+24]

      =\frac{1}{3}[(x^{2}-2(3x)+9)+15]

      =\frac{1}{3}[(x-3)^2+15]

      =\frac{1}{3}(x-3)^2+5

ii). Since, the parabolic graph for the given equation opens upwards,

    Vertex of the parabola will be the lowest point of the rider on the roller coaster.

    From the equation,

    Vertex → (3, 5)

    Therefore, minimum height of the rider will be the y-coordinate of the vertex.

    Minimum height of the rider = 5 m

iii). If h = 8 m,

    8=\frac{1}{3}(x-3)^2+5

    3=\frac{1}{3}(x-3)^2

    (x - 3)² = 9

    x = 3 ± 3

    x = 0, 6 m

    Therefore, at 8 m height of the roller coaster, horizontal distance of the rider will be x = 0 and 6 m

6 0
3 years ago
Which factor does the width of the peak of a normal curve depend on?
Aleks [24]
<span>The normal curve is described by a bell curved graph. The bell curved graph of a normal distribution depends on two factors: the mean and the standard deviation. The mean identifies the position of the center and the standard deviation determines the height and width of the bell. Therefore, the factor that the width of the peak of the normal curve depends on is the standard deviation.</span>
4 0
3 years ago
Read 2 more answers
The table of values represents a quadratic function. What is the average rate of change for f(x) from x = 0 to x = 10 ? Enter yo
Elena-2011 [213]
By definition we have that the average rate of change is given by:
 AVR = (f (x2) - f (x1)) / (x2 - x1)
 Substituting the values we have:
 AVR = (204 - (-6)) / (10 - 0)
 Rewriting we have:
 AVR = (204 + 6) / (10 - 0)
 AVR = 210/10
 AVR = 21
 Answer:
 
the average rate of change for f (x) from x = 0 to x = 10 is:
 
AVR = 21
8 0
4 years ago
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