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3 years ago

Calculate the theoretical efficiency for an Otto cycle engine with γ=1.40 and compression ration r=9.50.

Engineering

1 answer:

DENIUS [597]3 years ago

7 0

Answer:

The theoretical efficiency of the Otto engine is 59.4 percent.

Explanation:

The theoretical efficiency for Otto engine ( $\eta$ ), dimensionless, is obtained by this formula after supossing that fluid is an ideal gas:

$\eta = 1-\frac{1}{r^{\gamma -1}}$

Where:

$r$ - Compression ratio, dimensionless.

$\gamma$ - Heat capacity ratio, dimensionless.

Given that $r = 9.50$ and $\gamma = 1.40$ , the theoretical efficiency of the Otto engine is:

$\eta = 1 - \frac{1}{9.50^{1.40-1}}$

$\eta = 0.594$

The theoretical efficiency of the Otto engine is 59.4 percent.

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The Accenture team is involved in helping a client in the transformation journey using Cloud computing. How is myNav beneficial

professor190 [17]

Answer:

It helps ensure the security of client data.

Explanation:

Cloud computing is one of the security features in networking which is being adopted by big corporations and organizations inorder to ensure smooth running of the organization.

Also, due to the sensitivity of data which some organizations deals in, they tried everything possible to protect themselves and their clients' information through use of cloud computing. Data are stored in the clouds, and requires special administrative rights for it to be accessed by some of the staffs working in any given organization.

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3 years ago

Which of the following material properties varies with temperature? a)- density b)- viscosity c)- electrical resistance d)- all

Reil [10]

Answer:

(d) all of the above

Explanation:

Effect on the density of temperature: If we increase the temperature of any room then particles of the room moves and to and fro and so density is decrease

Effect on the viscosity of temperature : viscosity is inversely proportional to the temperature if we increase the temperature viscosity decreases and if we decrease the temperature viscosity increases.

Effect on the resistance of temperature : For metals if we increase the temperature then resistance increases and for semiconductor if we increase the temperature resistance decreases

So from above discussion all the parameter depends on the temperature so option (d( will be the correct option

6 0

3 years ago

Stone has been used as a building material since ancient times because of its compressive strength, which is the __________.

Doss [256]

Complete Question:

Stone has been used as a building material since ancient times because of its compressive strength, which is the?

Group of answer choices

A. ability to support pressure without breaking.

B. ability to press down and become solidly fixed in the ground.

C. relative weight of a block of stone to its size.

D. force a block exerts on the blocks around it.

Answer:

A. ability to support pressure without breaking.

Explanation:

Stone has been used as a building material since ancient times because of its compressive strength, which is the ability to support pressure without breaking.

Compressive strength can be defined as the ability of a structural element or particular material to withstand an applied, which is aimed at reducing the size of the structural element.

Simply stated, it is the ability of a structural element or material to withstand an applied load without deflections, fracture or having any crack.

In this context, a stone possesses the ability to resist or withstand compression loads.

Some examples of other materials or structural elements having good compressive strength are steel, bones, concrete etc. The standard unit of measurement of the compressive strength of a material is Mega Pascal (MPa) or pound-force per square inch (psi) in the United States of America.

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4 years ago

Which article of the NEC describes the proper placement of outlets in this type of room? Also, based on the given load what type

zmey [24]

The Article of the NEC that describes the proper placement of outlets in rooms is the Article 210.

NEC is the short or acronym for National Electric Code.

For example, with regard to Receptacles, section (210-21(b)) of the Article 100 indicates that a "Receptacle" is a contact device provided at an outlet for the connecting of an attachment plug.

The terms "receptacle" and "receptacles" occur often in the National Electrical Code (NEC).

Learn more about NEC at;
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7 0

2 years ago

A specimen of a 4340 steel alloy with a plane strain fracture toughness of 54.8 Mpa root m is exposed to a stress of 1030 MPa. W

cupoosta [38]

Answer:

It will not experience fracture when it is exposed to a stress of 1030 MPa.

Explanation:

Given

Klc = 54.8 MPa √m

a = 0.5 mm = 0.5*10⁻³m

Y = 1.0

This problem asks us to determine whether or not the 4340 steel alloy specimen will fracture when exposed to a stress of 1030 MPa, given the values of KIc, Y, and the largest value of a in the material. This requires that we solve for σc from the following equation:

σc = KIc / (Y*√(π*a))

Thus

σc = 54.8 MPa √m / (1.0*√(π*0.5*10⁻³m))

⇒ σc = 1382.67 MPa > 1030 MPa

Therefore, the fracture will not occur because this specimen can handle a stress of 1382.67 MPa before experience fracture.

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3 years ago