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Ilia_Sergeevich [38]
2 years ago
9

If you measure the voltage across a diode and it measures 0.3 V, the diode is probably made of __________ and is __________ bias

ed.
Engineering
1 answer:
fgiga [73]2 years ago
3 0

Answer:

  • germanium
  • forward

Explanation:

The forward-biased voltage drop of a semiconductor diode depends on the material it is made of and the method of fabricating the junction.

<h3>Voltage drops</h3>

A silicon diode will have a voltage drop that can be estimated as 0.7 V. The actual value will depend on current and temperature.

A germanium diode will have a voltage drop closer to 0.3 V, again depending on current and temperature.

A Schottky diode may have a voltage drop between 0.2 and 0.3 V, so may be difficult to distinguish from a germanium diode.

If it measures 0.3 V, the diode is probably made of <u>germanium</u>, and is <u>forward</u> biased.

__

The reverse-biased voltage reading will generally match the open-circuit voltage of the testing device.

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Answer:

I=3A

Explanation:

From the question we are told that:

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8 0
3 years ago
A body is moving with simple harmonic motion. It's velocity is recorded as being 3.5m/s when it is at 150mm from the mid-positio
natima [27]

Answer:

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Explanation:

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V=2.5 m/s at x=225 mm   ------------2

Where x measured  from mid position.

We know that velocity in simple harmonic given as

V=\omega \sqrt{A^2-x^2}

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From equation 1 and 2

3.5=\omega \sqrt{A^2-0.15^2}    ------3

2.5=\omega \sqrt{A^2-0.225^2}   --------4

Now by dividing equation 3 by 4

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So    A=0.2826 m

A=282.6 mm

Now by putting the values of A in the equation 3

3.5=\omega \sqrt{A^2-0.15^2}

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Maximum acceleration

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a_{max}=60.35\ m/s^2

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T=\dfrac{2\pi}{\omega}

T=\dfrac{2\pi}{14.609}

T=0.42 sec

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Answer:

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