B,c and f are true,but I doubt about g cause I don't know anything about electron's dimention
<span>A </span>flexible container<span> at an </span>initial volume<span> of 7.14 </span>L contains<span> 7.51 </span>mol<span> of </span>gas<span>. </span>More gas<span> is</span>then added<span> to the </span>container until<span> it </span>reaches<span> a </span>final volume<span> of 17.7 </span>L<span>. </span>Assuming<span> the </span>pressure<span> and</span>temperature<span> of the </span>gas remain constant<span>, </span>calculate<span> the </span>number<span> of </span>moles<span> of </span>gas added<span> to the </span>container<span>.</span>
Answer is: the oxidation number of oxygen must decrease.
Oxidizing agent is element (substance) that gain electrons in chemical reaction.
For example, balanced chemical reaction: C + O₂ → CO₂.
Oxygen change oxidation number from 0 to oxidation number -2 (reduction) and carbon change from 0 to +4 (oxidation)
<span>At room temperature and atmospheric pressure, nothing happens when the two gasses are mixed. However, at high temperature and pressure (450C, 200atm), in the presence of an iron oxide catalyst, the production of ammonia is thermodynamically advantageous.</span>
The hybrid orbital of this molecule is 
. Hence, option C is correct.
<h3>What is hybridisation?</h3>
Hybridization is defined as the concept of mixing two atomic orbitals to give rise to a new type of hybridized orbitals.
In this compound, a hybrid orbital makes I-O bonds. Due to hybridization iodate should have tetrahedral geometry but because of the presence of lone pair of electrons the shape of 
the ion is pyramidal.
The hybrid orbital of this molecule is . Hence, option C is correct.
Learn more about hybridisation here:
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