Select the atoms that are likely to gain electrons to form anions:

How many grams and what is the limiting reactent?

gayaneshka [121]

Hello!

1) What is the limiting reactant?

The chemical equation for this reaction is:

2Al(OH)₃ → Al₂O₃ + 3H₂O

The Limiting Reactant is the one that is in the lowest amount in the reaction and determines how many moles are produced. You can see that in this chemical equation there is only one reactant since this reaction is a decomposition reaction. So, the limiting reactant is Al(OH)₃.

2) How many grams of water are produced?

The chemical equation for this reaction is:

2Al(OH)₃ → Al₂O₃ + 3H₂O

So, we are going to use the following conversion factor to go from grams of Al(OH)₃ to grams of water:

$17,8 g Al(OH)_3* \frac{1 mol Al(OH)_3}{78 g Al(OH)_3}* \frac{3 moles H_2O}{2 moles Al(OH)_3}* \frac{18,015 g H_2O}{1 mol H_2O} \\ =6,17 g H_2O$

So, 6,17 grams of Water are produced.

Have a nice day!

5 0

4 years ago

Which of the following isotopes is NOT considered to be a major threat to human health from nuclear fallout? a. strontium-90 b.

Nat2105 [25]

Ohhh it’s A) strontium

4 0

3 years ago

If 6.0g of carbon is heated in air the mass of the product obtained could be either 22.0g or 14.0g depending on the amount of ai

Gnom [1K]

In accordance with Dalton's Law of multiple proportions

<h3>Further explanation</h3>

Given

6.0g of carbon

22.0g or 14.0g of product

Required

related laws

Solution

the amount of air present ⇒ as an excess or limiting reactant

air(O₂) as a limiting reactant(product=14 g)

C+0.5O₂⇒CO

6 + 8 = 14 g

mol O₂=8 g : 32 g/mol=0.25

mol C = 6 g : 12 g/mol = 0.5(2 x mol O₂)

mol CO= 2 x mol O₂ = 0.5 mol = 0.5 x 28 g/mol = 14 g

air(O₂) as an excess reactant(product=22 g) an C as a limiting reactant

C+O₂⇒CO₂

6 + 16 = 22 g

mol C = 6 g : 12 g/mol = 0.5

mol O₂ = 16 g : 32 g/mol=0.5

mol CO₂ = 22 g : 44 g/mol = 0.5

if the mass firs element (C) constant, then the mass of the second element(O) in the two compounds will have a ratio as a simple integer.

CO = 6 : 8

CO₂ = 6 : 16

the ratio O = 8 : 16 = 1 : 2

In accordance with Dalton's Law of multiple proportions

4 0

3 years ago

If input energyis 100J and useful is 70J what is the waste energy

Oliga [24]

Answer:

waste energy = 30 J

Explanation:

Given that.

Input energy = 100 J

Useful energy = 70 J

We need to find the amount of waste energy.

Waste energy = total energy - used energy

= 100 J - 70 J

= 30 J

Hence, 30 J of energy is waste energy.

4 0

3 years ago

if callie has 1,012 beads. and she wants to divide the beads evenly to make 22 necklaces. how many beads will be used for each n

borishaifa [10]

1012/22 = 46

46 beads will be used in each necklace

hope this helps

7 0

3 years ago

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