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olga2289 [7]
3 years ago
10

Select the atoms that are likely to gain electrons to form anions:

Chemistry
1 answer:
sineoko [7]3 years ago
4 0
Fluorine and oxygen
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Assuming equal concentrations, rank these solutions by ph.? assuming equal concentrations, rank these solutions by ph. koh (aq h
polet [3.4K]
I remember coming across this question and the options were:
KOH, HCN, NH₃, HI, Sr(OH)₂

Now, a substance with a low pH is one that dissociates completely in water to release hydrogen ions, while basic substances dissociate completely to release hydroxide ions. Therefore, in the order of increasing pH:
HI, HCN, NH₃, Sr(OH)₂, KOH
7 0
3 years ago
What volumes of 0.200 M HCOOH and 2.00 M NaOH would make 500. mL of a buffer with the same pH as one made from 475 mL of 0.200 M
Fed [463]

<u>36 ml of NaOh and</u><u> 464 ml</u><u> of </u><u>HCOOH</u><u> would be enough to form 500 ml of a buffer with the same pH as the buffer made with </u><u>benzoic acid </u><u>and NaOH.</u>

What is benzoic acid found in?

  • Some natural sources of benzoic acid include: ​Fruits:​ Apricots, prunes, berries, cranberries, peaches, kiwi, bananas, watermelon, pineapple, oranges.
  • ​Spices:​ Cinnamon, cloves, allspice, cayenne pepper, mustard seeds, thyme, turmeric, coriander.

Calculate the amount of moles in NaOH and benzoic acid. This calculation is done by multiplying molarity by volume.

Amount of moles of NaOH -2 × 0.025 =  0.05 mol

Amount of moles of benzoic acid 2 × 0.475 = 0.095 mol

In this case, we can calculate the pH produced by the buffer of these two reagents, as follows

pH = pKa + log\frac{base}{acid}

4.2 + log\frac{0.05}{0.045} = 4.245

We must repeat this calculation, with the values shown for HCOOH and NaOH. In this case, we can calculate as follows

pH = pKa + log\frac{base}{acid}

4.245 = 3.75 + log\frac{base}{acid}

log\frac{base}{acid} = 0.5

\frac{base}{acid} = 3.162

Now we must solve the equation above. This will be done using the following values

\frac{2(0.5 - x)}{0.2x - 2(0.5 - x)} = 0.464 L

With these values, we can calculate the volumes of NaOH and HCOOH needed to make the buffer.

NaOH volume

( 0.5 - 0.464)L

0.036L .................... 36ml

HCOOH volume

500 - 36 = 464mL

Learn more about benzoic acid

brainly.com/question/24052816

#SPJ4

3 0
2 years ago
How many nanoseconds are there in one minute?
umka21 [38]
1 minute equals 6e+10 nanoseconds.
I hope this helped! :>
3 0
4 years ago
a magnet has a north and south pole labeled in the drawing student A thinks that if you cut a magnet in half each ew parts will
riadik2000 [5.3K]

Answer:

The student is Incorrect

Explanation:

Even if you break a magnet the poles still remains same. There is no

difference in the magnet Both north  and south pole will be there even if you

cut it in to small pieces when you cut it into pieces, if suppose you  break 2

magnets and put north and north together it will repel whereas if there  are  

different  poles like north and south it will attract, so even if you break one

single magnet the different poles will attract, Hence the student is incorrect.

Please mark me as brainliest

<h3><u>Thank you </u>:)</h3>

8 0
3 years ago
The Arrhenius theory explains how the concentration of H
koban [17]

Answer:true

Explanation:

7 0
2 years ago
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