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3 years ago

Find the length of leg a in a right triangle with leg b= 4 and hypotenuse C =5

Mathematics

1 answer:

Korolek [52]3 years ago

8 0

Answer:

Leg A = 3

Step-by-step explanation:

You use the equation A squared plus B squared equals C squared. Then, you substitute the value that you have, so the equation would be a squared plus 3 squared equals 5 squared. Next, you square the two values to make the equation a squared plus 16 equals 25. After that, you subtract one of the values (which in case is 16) on both that leg value and the hypotenuse, so you are left with A squared equals 9. Finally, you square both 9 and A squared and you are left with A = 3. I hope that helps you understand it clearly!

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Given a function I and a subset A of its domain, let I(A) represent the range of lover the set A; that is, I(A) = {I(x) : x E A}

Ede4ka [16]

Step-by-step explanation:

(a)

Using the definition given from the problem

$f(A) = \{x^2 \, : \, x \in [0,2]\} = [0,4]\\f(B) = \{x^2 \, : \, x \in [1,4]\} = [1,16]\\f(A) \cap f(B) = [1,4] = f(A \cap B)\\$

Therefore it is true for intersection. Now for union, we have that

$A \cup B = [0,4]\\f(A\cup B ) = [0,16]\\f(A) = [0,4]\\f(B)= [1,16]\\f(A) \cup f(B) = [0,16]$

Therefore, for this case, it would be true that $f(A\cup B) = f(A)\cup f(B)$ .

(b)

1 is not a set.

(c)

To begin with

$A\cap B \subset A,B$

Therefore

$g(A\cap B) \subset g(A) \cap g(B)$

Now, given an element of $g(A) \cap g(B)$ it will belong to both sets, therefore it also belongs to $g(A\cap B)$ , and you would have that

$g(A)\cap g(B) \subset g(A \cap B)$ , therefore $g(A)\cap g(B) = g(A \cap B)$ .

(d)

To begin with $A,B \subset A \cup B$ , therefore

$g(A) \cup g(b) \subset g(A\cup B)$

7 0

3 years ago

Karina says every equilateral triangle is acute. Is this true explain

LenaWriter [7]

Yes, every equilateral triangle is acute because the angles are always congruent(identical) and 60 degrees which is acute. But I may be wrong. :P

5 0

3 years ago

What is the probability of picking an orange marble and flipping tails? 1/7 1/14 2/14 8/14

vladimir2022 [97]

Answer:

Flipping tails would be 1/2 but how many marbles are there and how many orange ones are there?

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

ACCTUALLY HELP ME??!!!!!!! NEEDED FOR TOMORROW AND 50 POINTS! will award brainliest for first answer!!

drek231 [11]

Answer:

a:c = 35:24

a:c = 20:27

a:c = 35:22

a:c = 28:27

Step-by-step explanation:

a:b = 7:3

Using cross products

3a = 7b

Divide by 7

3a/7 = b

Now we want

8b = 5c

Substitute in 3a/7 for b

8 (3a/7) = 5c

24/7a = 5c

Multiply by 7

24/7a *7 = 5*7c

24a = 35c

Divide by c

24 a/c = 35

Divide by 24

a/c = 35/24

a:c = 35:24

a:b = 4:9

Using cross products

9a = 4b

Divide by 4

9a/4 = b

Now we want

3b = 5c

Substitute in 9a/4 for b

3 (9a/4) = 5c

27/4a = 5c

Multiply by 4

27/4a *4 = 5*4c

27a = 20c

Divide by c

27 a/c = 20

Divide by 27

a/c = 20/27

a:c = 20:27

b:c = 5:11

Using cross products

11b = 5c

Divide by 11

b = 5c/11

Now we want

2a = 7b

Substitute in 5c/11 for b

2a = 7(5c/11)

2a = 35c/11

Multiply by 11

2a*11 = 35c

22a = 35c

Divide by c

22 a/c = 35

Divide by 22

a/c = 35/22

a:c = 35:22

b:c = 14:3

Using cross products

3b = 14c

Divide by 3

b = 14c/3

Now we want

9a = 2b

Substitute in 14c/3 for b

9a = 2(14c/3)

9a = 28c/3

Multiply by 3

9a*3 = 28c

27a = 28c

Divide by c

27 a/c = 28

Divide by 27

a/c = 28/27

a:c = 28:27

7 0

3 years ago

If AC = 20 centimeters, and BC = 16 centimeters, which does AB equal?

Anna11 [10]

Answer:

The answer is B. 12 cm

Step-by-step explanation:

ABC is a right triangle

AB and BC are the legs and AC is the hypotenuse.

The Pythagorean theorem a^2 + b^2 = c^2 can be manipulated to solve for a and get 12.

8 0

3 years ago