<span>280
I'm assuming that this question is badly formatted and that the actual number of appetizers is 7, the number of entres is 10, and that there's 4 choices of desserts. So let's take each course by itself.
You can choose 1 of 7 appetizers. So we have
n = 7
After that, you chose an entre, so the number of possible meals to this point is
n = 7 * 10 = 70
Finally, you finish off with a dessert, so the number of meals is:
n = 70 * 4 = 280
Therefore the number of possible meals you can have is 280.
Note: If the values of 77, 1010 and 44 aren't errors, but are actually correct, then the number of meals is
n = 77 * 1010 * 44 = 3421880
But I believe that it's highly unlikely that the numbers in this problem are correct. Just imagine the amount of time it would take for someone to read a menu with over a thousand entres in it. And working in that kitchen would be an absolute nightmare.</span>
<span>x(3x+5)-4(3x+5)
3x^2+5x-12x+20
3x^2-7x+20</span>
12 × 2 = 24
anything to ask please pm me
Answer:
99% confidence interval estimate of the mean weight time for a population with drug treatments
(79.11 , 112.69)
Step-by-step explanation:
<u><em>Step(i):</em></u>-
Given data mean of the Population = 104 minutes
Given sample size 'n' =14
Mean of the sample(x⁻) = 95.9 minutes
Given Standard deviation = 24.4 minutes
<u><em>Step(ii)</em></u>:-
99% confidence interval estimate of the mean weight time for a population is determined by
On calculation , we get
(95.9 -16.79 , 95.9 +16.79)
(79.11 , 112.69)
<u><em>Conclusion:</em></u>-
99% confidence interval estimate of the mean weight time for a population with drug treatments
(79.11 , 112.69)
