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3 years ago

Calculate the amount of heat required to raise the temperature of a 24 g sample of water from 9°C to 23°C.

Chemistry

1 answer:

borishaifa [10]3 years ago

7 0

Answer:

1400KJ/mol⁻¹

Explanation:

Amount of heat required can be found by:

Q = m × c × ΔT

Where m is the mass, c is the specific heat capacity (4.2KJ for water) and ΔT is the change in temperature.

Q = 24 × 4.2 × (23 - 9)

= 24 × 4.2 × 14

= 1411.2KJ/mol⁻¹

= 1400KJ/mol⁻¹ (to 2 significant figures)

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How many grams of oxygen are required to react with 13.0 grams of octane (C8H18) in the combustion of octane in gasoline?

egoroff_w [7]

Grams of oxygen are required to react with 13.0 grams of octane (C8H18) in the combustion of octane in gasoline is 45.5g

Octane is a hydrocarbon which burns in gasoline in presence of oxygen according to the given balanced chemical equation,

2C₈H₁₈ + 25O₂------> 16CO₂ + 18H₂0

Molar mass of octane = 114.23g/mol

Molar mass of Oxygen = 32g/mol

According to the stiochiometry of the balanced equation the mole ratio of Octane and Oxygen is 2:25

2 mole of octane needs 25 mole of oxygen

1 mole of octane needs 12.5 moleof oxygen

114.23g of octane needs 400g of oxygen

13g of octane needs 45.5g of oxygen

Mass of oxygen needed =45.5g

Hence, the Mass of oxygen needed is 45.5g for the combustion of octane in gasoline.

Learn more about Octane here, brainly.com/question/21268869

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2 years ago

Select the correct answer. Based on the reactivities of the elements involved, which reaction will form products that are more s

FinnZ [79.3K]

Answer: The correct answer is option B.

Explanation: Reactivity of elements is defined as the tendency to loose or gain electrons.

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The element which lies above in the reactivity series can easily displace the element which lies below in the reactivity series.

Option A: This reaction will not yield a stable product because Zinc lies below Aluminium in the reactivity series.

$AlBr_3+Zn\rightarrow \text{No reaction}$

Option B: This reaction will yield a stable product because Sodium lies above Calcium in the reactivity series.

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$MgBr_2+H_2\rightarrow \text{No reaction}$

Option D: This reaction will not yield a stable product because Calcium lies below Barium in the reactivity series.

$BaBr_2+Ca\rightarrow \text{No reaction}$

Option E: This reaction will not yield a stable product because barium lies below Lithium in the reactivity series.

$2LiBr+Ba\rightarrow \text{No reaction}$

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