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2 years ago

A force of 100 newtons was necessary to lift a tree. A total of 50 joules of work was done. How far was the tree lifted

Chemistry

1 answer:

defon2 years ago

4 0

Answer:

Distance lift the tree = 0.5 m

Explanation:

Given:

Work done = 50 joules

Force = 100 newton

Find:

Distance lift the tree

Computation:

Distance = Work done / Force

Distance = 50 / 100

Distance = 0.5 m

Distance lift the tree = 0.5 m

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Fynjy0 [20]

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2 years ago

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Which compound is produced when HCl(aq) is neutralized by Ca(OH)2(aq)?

kiruha [24]

Answer: The correct answer is Option 1.

Explanation:

Neutralization reaction is defined as the reaction in which acid reacts with a base to produce a salt along with water.

Here, HCl is an acid and $Ca(OH)_2$ is a base. When these two compounds react, the salt obtained is calcium chloride.

The equation for the above reaction is given by:

$2HCl(aq.)+Ca(OH)_2(aq.)\rightarrow CaCl_2(s)+2H_2O(l)$

Hence, the correct answer is Option 1.

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2 years ago

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A 2.5 g sample of french fries is placed in a calorimeter with 500.0 g of water at an initial temperature of 21 °C. After combus

SIZIF [17.4K]

Q=m°CΔT
=(500g) x (1 cal/g.°C) x (48°C-21°C) = 13500 cal
13500 cal / 1000 = 13.5 kcal

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3 years ago

How many moles of Al are necessary to form 23.6 g of AlBr₃ from this reaction: 2 Al(s) + 3 Br₂(l) → 2 AlBr₃(s) ?

Gnoma [55]

Answer:

0.088 mole of Al.

Explanation:

First, we shall determine the number of mole in 23.6 g of AlBr₃.

This is illustrated below:

Mass of AlBr₃ = 23.6 g

Molar Mass of AlBr₃ = 27 + 3(80) = 267 g/mol

Mole of AlBr₃ =.?

Mole = mass/Molar mass

Mole of AlBr₃ = 23.6 / 267

Mole of AlBr₃ = 0.088 mol

Next, we shall writing the balanced equation for the reaction.

This is given below:

2Al(s) + 3Br₂(l) → 2AlBr₃(s)

From the balanced equation above,

2 moles of Al reacted with 3 mole of Br₂ to 2 moles AlBr₃.

Finally, we shall determine the number of mole of Al needed for the reaction as follow:

From the balanced equation above,

2 moles of Al reacted to 2 moles AlBr₃.

Therefore, 0.088 mole of Al will also react to produce 0.088 mole of AlBr₃.

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3 years ago