A. Distillation. If the mixtures have different boiling points, the liquid with the lower boiling point will distill off first, followed by the other one.
“B. Filtration” is <em>incorrect</em>. Both liquids will pass through the filter paper.
“C. Sedimentation” is <em>incorrect </em>because it works only for a solid suspended in a liquid.
“D. Evaporation” is <em>incorrect</em>. Both liquids will pass into the atmosphere never to be seen again.
Answer:
The answer is freezing (Option B)
Explanation:
To begin with, it is important to note that lava flowing from Hawaiian volcanoes are not sticky but very runny. They cool down or freeze after flowing a long way.
Since the lava is not sticky (because it is not thick), it means they are thin and prone to freezing or cooling immediately when the flow stops. Upon freezing, the lava forms crystal rocks (shiny in texture and gray in color) that are not big.
The correct answer of the given question above would be option B. IRON 0.449. Based on the given details above about an unknown substance that has a mass of 14.7 g and the substance absorbs 1.323×102 J of heat, the temperature of the substance is raised from 25.0 ∘C to45.0 ∘C, most likely, the substance is IRON. Hope this answers the question.
Amylose in starch is responsible for the formation of a deep blue color in the presence of iodine. The iodine molecule slips inside of the amylose coil. ... This makes a linear triiodide ion complex with is soluble that slips into the coil of the starch causing an intense blue-black color. I got this from google for a more detailed response, and hope this helps!
Answer:
A. The reaction will proceed forward forming more CH4
B. The reaction will proceed forward forming more CH4
C. Since the reaction is exothermic, raising the temperature will cause the reaction to proceed backward, thus forming C and H2.
D. Lowering the volume makes the gas particles to be more close together thereby enhancing their collisions leading to reaction. Therefore the reaction will proceed forward forming more CH4
E. Catalyst only reduce the activation energy so the reaction can proceed faster. The reaction will proceed forward forming.
F. The following will favour CH4 at equilibrium
i. Catalyst to the reaction mixture,
ii. Both adding more H2 to the reaction mixture and lowering the volume of the reaction mixture
iii. Adding more C to the reaction mixture.