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sukhopar [10]
3 years ago
13

In the figure, ∠6 and ∠3 are ...

Mathematics
1 answer:
konstantin123 [22]3 years ago
7 0

Answer:

They're supplementary angles AND same-side interior angles.

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Can someone tell me what is the slope of the line that includes points (4,-10) and (6,8)
miss Akunina [59]

Answer: hmmm no!

Step-by-step explanation:

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3 years ago
Pls help fraction and percent word problem
vagabundo [1.1K]
<h2>>> Answer </h2>

_________

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2012 - 2013 = +20%

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3 years ago
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A gas pump measures volume of gas to the nearest 0.01 gallon. Which measurement shows an appropriate level of precision for the
PSYCHO15rus [73]

Answer:

12.3 Gallons

Step-by-step explanation:

Options of the question:-

Option A. 12.33 gallons

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Option D. 12.3 gallons

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5 0
3 years ago
The average value of a function f over the interval [−2,3] is −6 , and the average value of f over the interval [3,5] is 20. Wha
Xelga [282]

Answer:

The average value of f over the interval [-2,5] is \frac{10}{7}.

Step-by-step explanation:

Let suppose that function f is continuous and integrable in the given intervals, by integral definition of average we have that:

\frac{1}{3-(-2)} \int\limits^{3}_{-2} {f(x)} \, dx = -6 (1)

\frac{1}{5-3} \int\limits^{5}_{3} {f(x)} \, dx = 20 (2)

By Fundamental Theorems of Calculus we expand both expressions:

\frac{F(3)-F(-2)}{3-(-2)} = -6

F(3) - F(-2) = -30 (1b)

\frac{F(5)-F(3)}{5-3} = 20

F(5) - F(3) = 40 (2b)

We obtain the average value of f over the interval [-2, 5] by algebraic handling:

F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)

F(5) - F(-2) = 10

\frac{F(5)-F(-2)}{5-(-2)} = \frac{10}{5-(-2)}

\bar f = \frac{10}{7}

The average value of f over the interval [-2,5] is \frac{10}{7}.

4 0
3 years ago
+3=17
aev [14]

Answer:

1

Step-by-step explanation:

5 0
2 years ago
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