Answer:
1-50
2-90
3-60
4-60
5-60
6-60
7-100
Step-by-step explanation:
Answer:
<h3>
∠XYZ = 102</h3><h3>
</h3>
Step-by-step explanation:
<u>1st step is to solve x from ΔWXY</u>
∠W + ∠X + ∠Y = 180
where ∠W = 5x + 2
∠X = 7x + 4
∠Y = 180 - (15x - 18)
= 198 - 15x
now plugin values into the equation:
5x + 2 + 7x + 4 + 198 - 15x = 180
combine similar terms:
5x + 7x - 15x = 180 - 2 - 4 - 198
simplify:
-3x = -24
x = -24 / -3
x = 8
<u>2nd step is to substitute x = 8 into ∠XYZ</u>
∠XYZ = 15x - 18
∠XYZ = 15(8) - 18
∠XYZ = 102
Answer:
You've completed 11/12 of your project
Only 1/12 left to go!
Step-by-step explanation:
2/3 + 1/4 = 11/12
Answer:
17 1/2
Step-by-step explanation:
21 - 3 1/2 = 17 1/2
Dale drove to the mountains last weekend. there was heavy traffic on the way there, and the trip took 7 hours. when dale drove home, there was no traffic and the trip only took 5 hours. if his average rate was 18 miles per hour faster on the trip home, how far away does dale live from the mountains? do not do any rounding.
Answer:
Dale live 315 miles from the mountains
Step-by-step explanation:
Let y be the speed of Dale to the mountains
Time taken by Dale to the mountains=7 hrs
Therefore distance covered by dale to the mountain = speed × time = 7y ......eqn 1
Time taken by Dale back home = 5hours
Since it speed increased by 18 miles per hour back home it speed = y+18
So distance traveled home =speed × time = (y+18)5 ...... eqn 2
Since distance cover is same in both the eqn 1 and eqn 2.
Eqn 1 = eqn 2
7y = (y+18)5
7y = 5y + 90
7y - 5y = 90 (collection like terms)
2y = 90
Y = 45
Substitute for y in eqn 1 to get distance away from mountain
= 7y eqn 1
= 7×45
= 315 miles.
∴ Dale leave 315 miles from the mountains
