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3 years ago

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Mathematics

1 answer:

mixer [17]3 years ago

8 0

Answer:

0.2 lb of ham in decimal digits

Step-by-step explanation:

At a grocery store, you want to buy 2/1/10 lb of ham

2 / 1 divided by 10

2/1 = 2 so now

2/ 10 = 1/ 5

Hence, 0.2lb of ham in decimal digits

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I need this done it’s due tmr and I need each problem simplified in the lowest fraction

Ivenika [448]

Answer:

photomath

Step-by-step explanation:

theres an app where you can take a pic of your problem and it would solve it for you,including fractions. I'm pretty sure it will simplify your answers too.The app is called photomath

8 0

3 years ago

1)A System of equations is shown below . What is the solution to the system of equations? 5x+2y=-15 2x-2y=-6

meriva

Answer:

x= -3 and y= 0

Step-by-step explanation:

5x+2y=-15

x= -3

Putting value of x in equation 1

5(-3) +2y=-15

-15+2y= -15

2y= 0

y= 0

This can be solved with the help of matrices

In matrix form the above equations can be written in the form

$\left[\begin{array}{ccc}5&2\\2&-2\/\end{array}\right]$ $\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ = $\left[\begin{array}{ccc}-15\\-6\\\end{array}\right]$

Let

$\left[\begin{array}{ccc}5&2\\2&-2\/\end{array}\right]$ = A $\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ = X and $\left[\begin{array}{ccc}-15\\-6\\\end{array}\right]$ = B

Then AX= B

or X= A⁻¹ B

where A⁻¹= adj A/ ║A║ where mod A≠ 0

adj A= $\left[\begin{array}{ccc}-2&-2\\-2&5\/\end{array}\right]$

║A║= ( 5*-2- 2*2)= -10-4= -14≠0

X= A⁻¹ B

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ =- 1/14 $\left[\begin{array}{ccc}-2&-2\\-2&5\/\end{array}\right]$ $\left[\begin{array}{ccc}-15\\-6\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ =- 1/14 $\left[\begin{array}{ccc}-2*-15&+ -2*-6\\-2*-15&+ 5*-6\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ =- 1/14 $\left[\begin{array}{ccc} 30&+12\\30&+-30\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ =- 1/14 $\left[\begin{array}{ccc}42\\0\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ = $\left[\begin{array}{ccc}-42/14\\0/-14\\\end{array}\right]$

$\left[\begin{array}{ccc}x\\y\\\end{array}\right]$ = $\left[\begin{array}{ccc}-3\\0\\\end{array}\right]$

From here x= -3 and y= 0

Solution Set = [(-3,0)]

3 0

3 years ago

Which expressions are equivalent to ( 10 x 18) + (10 x s)

kolezko [41]

Answer:

10×18=180

180+(10s)

if it is equal to zero

s is -18

4 0

3 years ago

Find the equation of the line that is parallel to x=6y-5 and that passes through (5,-3). express answer in standard form

Anestetic [448]

Answer:

Final answer is $x-6y=23$

Step-by-step explanation:

We need to find the equation of the line that is parallel to x=6y-5 and that passes through (5,-3).

So first we need to find the slope of given line.

rewirite x=6y-5 in y=mx+b form

x+5=6y

$\frac{1}{6}x+\frac{5}{6}=y$

Compare given equation with y=mx+b

we get: m=1/6

We know that parallel equations has equal slope.

Then slope of required line m=1/6

Now plug the given point (5,-3) and slope m=1/6 into point slope formula:

$y-y_1=m\left(x-x_1\right)$

$y-(-3)=\frac{1}{6}\left(x-5\right)$

$y+3=\frac{1}{6}x-\frac{5}{6}$

$y=\frac{1}{6}x-\frac{5}{6}-3$

$y=\frac{1}{6}x-\frac{23}{6}$

Now we need to rewrite that equation in standard form. Ax+By=C.

6y=x-23

x-23=6y

x-6y=23

Hence final answer is $x-6y=23$

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3 years ago

I need help now I don't get this

Darina [25.2K]

The answer is $1.80. You would take 25% of 3, which is 75, and subtract it from 3. That leaves you with $2.25, which you take 20% off, which is 0.45, and subtract that from 2.25. That leaves you with a grand total of $1.80. Hope that this helped!

3 0

3 years ago

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