Statement 1: WXYZ is a kite
Reason 1: Given
Statement 2: WX = XY and WZ = YZ
Reason 2: Definition of a kite
Statement 3: XZ = XZ
Reason 3: Reflexive property
Statement 4: Triangle WXZ = Triangle YXZ
Reason 4: SSS Congruence
Statement 5: Angle W = Angle Y
Reason 5: CPCTC
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Extra notes:
* A kite is a quadrilateral that has two pairs of adjacent congruent sides. In this case, WX and XY is one pair of congruent sides that are adjacent (ie next to each other). So that's why WX = XY. Similarly, WZ = YZ is the second pair of adjacent congruent sides.
* Draw in a segment from point X to point Z to help form two triangles. The two triangles are congruent as proven in statement 4. One triangle is a reflection over the line XZ to get the other triangle.
* Due to this reflection, angle W reflects over line XZ to get angle Y. Proving that angle W = angle Y
* SSS means "side side side", basically saying "you use three pairs of congruent sides to prove two triangles congruent".
* The acronym CPCTC stands for "corresponding parts of congruent triangles are congruent"
Answer:
21
Step-by-step explanation:
You do the parentheses first, so 27/9 = 3
10-3 = 7
3 * 7 = 21
Answer:
Step-by-step explanation:
There are two ways to do this. You could use your calculator to find out the decimal numbers that are equivalent to the two given fractions. Then check which one of the givens falls between these two numbers. I wouldn't do it that way -- not when you are told that the answer has 56 as the denominator. So ...
The best way to do it is to change the two givens so that they have a denominator of 56
3/7 = 3*8/7*8 = 24 / 56
7*7 / 7*8 = 49 / 46
So you need a number that is between 49 and 24
There is only one 27 / 56
Answer: In particular, let’s focus our attention on the behavior of each graph at and around . 2 and x= -1 for x < 2. There are open circles at both endpoints (2, 1) and (-2, 1). The third is h (x) = 1 / (x-2)^2, in which the function curves asymptotically towards y=0 and x=2 in quadrants one and two."
Step-by-step explanation: I think this is the problem ur on