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3 years ago

12

We say that evaporation is a cooling process. (a) What cools and what warms? We say that condensation is a warming process. (b)

What warms and what cools?

1 answer:

alekssr [168]3 years ago

8 0

Answer:

a liquid warms gas cools

b solid piece warms and liquid cools

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What are things that we can do to protect our climate for future generations?

Vilka [71]

<span>Reduce energy use.
Change the way you think about transportation. Walk or bike whenever possible.
Insulate your home. Insulate yourself and your home.
Make every drop count.
</span>Cool wash and hang to dry.
<span>Switch to "green power.
</span>Recycle.

6 0

3 years ago

the resistivity of gold is 2.44×10−8Ω⋅m at room temperature. A gold wire that is 0.9 mm in diameter and 14 cm long carries a cur

cricket20 [7]

Answer:

0.03605 V/m is the electric field in the gold wire.

Explanation:

Resistivity of the gold = $\rho = 2.44\times 10^{-8} \Omega.m$

Length of the gold wire = L = 14 cm = 0.14 m ( 1 cm = 0.01 m)

Diameter of the wire = d = 0.9 mm

Radius of the wire = r = 0.5 d = 0.5 × 0.9 mm = 0.45 mm = $0.45\times 0.001 m$

( 1mm = 0.001 m)

Area of the cross-section = $A=\pi r^2=\pi r^(0.45\times 0.001 m)^2$

Resistance of the wire = R

Current in the gold wire = 940 mA = 0.940 A ( 1 mA = 0.001 A)

$R=\rho\times \frac{L}{A}$

$V(voltage)=I(current)\times R(Resistance)$ ( Ohm's law)

$\frac{V}{I}=\rho\times \frac{L}{A}$

We know, Electric field is given by :

$E=\frac{dV}{dr}$

$E=\frac{V}{L}$

$E=\frac{V}{L}=\rho\times \frac{I}{A}$

$E=2.44\times 10^{-8} \Omega.m\times \frac{0.940 A}{\pi r^(0.45\times 0.001 m)^2}=0.03605 V/m$

0.03605 V/m is the electric field in the gold wire.

3 0

4 years ago

1. The uniform seesaw is balanced at its center of mass. The smaller boy on the right has a mass of m = 40.0 kg. What is the mas

tankabanditka [31]

Answer:

Explanation:

Find the complete question attached

Using the principle of moment

Clockwise moment = Anticlockwise moment

AntiClockwise moment = M × 2.0

ACW moment = 2M

Clockwise moment = 40×4

Clockwise moment = 160kgcm

Equate both expression and calculate M

2M = 160

M = 160/2

M = 80kg

Hence the mass of his friend is 80kg

4 0

4 years ago

Bumper car A (281 kg) moving

solmaris [256]

use consevation of linear momentum

m1v1+m2v2=(M1+M2)V3
281(2.82)+209(-1.72)=(209+281)V2
792.42-359.48=490v3
432.9=490v3
V3=0.88m/s

4 0

2 years ago

a car moving with 72 km/hr towards east and another car with 90km/hr towards west find relative of A w.r to B

hodyreva [135]

Answer:

please tell me what does w.r mean ? then I will try to give answer

7 0

3 years ago