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</span>Cool wash and hang to dry.
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Answer:
0.03605 V/m is the electric field in the gold wire.
Explanation:
Resistivity of the gold = 
Length of the gold wire = L = 14 cm = 0.14 m ( 1 cm = 0.01 m)
Diameter of the wire = d = 0.9 mm
Radius of the wire = r = 0.5 d = 0.5 × 0.9 mm = 0.45 mm = 
( 1mm = 0.001 m)
Area of the cross-section = 
Resistance of the wire = R
Current in the gold wire = 940 mA = 0.940 A ( 1 mA = 0.001 A)

( Ohm's law)

We know, Electric field is given by :




0.03605 V/m is the electric field in the gold wire.
Answer:
Explanation:
Find the complete question attached
Using the principle of moment
Clockwise moment = Anticlockwise moment
AntiClockwise moment = M × 2.0
ACW moment = 2M
Clockwise moment = 40×4
Clockwise moment = 160kgcm
Equate both expression and calculate M
2M = 160
M = 160/2
M = 80kg
Hence the mass of his friend is 80kg
use consevation of linear momentum
- m1v1+m2v2=(M1+M2)V3
- 281(2.82)+209(-1.72)=(209+281)V2
- 792.42-359.48=490v3
- 432.9=490v3
- V3=0.88m/s
Answer:
please tell me what does w.r mean ? then I will try to give answer