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2 years ago

A 7 kg ball of clay traveling at 12 m/s collides with a 25 kg ball of clay traveling in the

Physics

1 answer:

ANEK [815]2 years ago

4 0

Answer:

Given: 

m1 = 7 kg

V1 = 12 m/s

m2 = 25 kg

V2 = 6 m/s

To find:

Combined speed of two balls stick together after collision V = ?

Solution:

According to law of conservation of momentum,

m1V1 + m2V2 = (m1+m2)V

7×12 + 25×6 = (7+25)V

84 + 150 = 32V

V = 234/32

V = 7.31 m/s

Combined speed of two ball is 7.31 m/s

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A locomotive accelerates a 25-car train along a level track. Every car has a mass of 7.7 ✕ 104 kg and is subject to a friction f

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To solve the problem it is necessary to apply the concepts related to Force of Friction and Tension between the two bodies.

In this way,

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$m_T = 25(7.7*10^4)Kg$

$m_T = 1.925*10^6Kg$

Therefore the friction force at 29Km / h would be,

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