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Luba_88 [7]
3 years ago
12

Where does the atmosphere of the Earth end? (i.e. Where is the top of the Earth's atmosphere?) Where does the atmosphere of the

Earth end? (i.e. Where is the top of the Earth's atmosphere?)
a. The tops of thunderstorms are at the top of the Earth's atmosphere.

b. There is no definite top to the atmosphere. The pressure and density gradually get smaller as the altitude gets larger.

c. The top of the Earth's atmosphere is about 100 kilometers below the orbit of the International Space Station.

d. The Earth's atmosphere ends at the point where the aurora (Northern Lights) begin.
Physics
1 answer:
galben [10]3 years ago
7 0

Answer:

b. There is no definite top to the atmosphere. The pressure and density gradually get smaller as the altitude gets larger.

Explanation:

There is no specific top of the atmosphere. It varies from place to place. But generally it is considered to be 480 kilometers thick.  But majority of its thickness is limited to 16 km only above earth surface. The pressure and density gradually get smaller as the altitude gets larger. The air pressure at sea level is 14.7 pounds per square inch and it decreases to 10 pounds per square inch at a height of 3 kilometers. From the above discussion we say that option B is correct

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what is the force of friction between an 80kg box and the ground on Earth if the coefficient is 0.2?​
Reil [10]

Answer:

160N

Explanation: When 80kg mass is one group . It's reaction force acting on a ground.

Weight of the object = 80*10

= 800 N

Here we are given cofficient of static friction its 0.2. It should be smaller than 1

Friction force = Reaction * Friction Cofficient

Reaction = 800N ( Considering Vertical Equilibrium )

F = 800* 0.2

F = 160N

3 0
3 years ago
Read 2 more answers
A fireworks shell is accelerated from rest to a velocity of 68.0 m/s over a distance of 0.230 m.
Ugo [173]

Answer:

(A) 10052.2 m/s²

(B)  0.00678 seconds

Explanation:

From the question,

(A) Applying

V² = U²+2as..................... Equation 1

Where V = Final velocity, U = Initial velocity, a = acceleration due to gravity, s = distance.

make a the subject of the  equation

a = (V²-U²)/2s........................ Equation 2

Given: U = 0 m/s( from rest), V = 68 m/s, s = 0.230 m

Substitute these values into equation 2

a = (68²-0²)/(2×0.230)

a = 10052.2 m/s²

(B) Using,

a = (V-U)/t......................... Equation 3

Where t= time.

make t the subject of the equation

t = (V-U)/a......................... Equation 4

Given: V = 68 m/s, U = 0 m/s, a = 10052.2

Substitute into equation 4

t = (68-0)/10052.2

t = 0.00678 seconds

5 0
3 years ago
Plz Help me This is all my homework The one is orange is the ones i need help in
IrinaVladis [17]

Convection is the transfer of heat through a fluid

Conduction is the heat or electric current from one substance to another

Radiation is energy that radiated or transmitted

Ex: Convection- A pot of water is being boiled- the heat is being transferred to to the water

Ex2: Conduction- I have a plate filled with hot food- the heat from the food is being transferred to the plate, making the plate hot as well.

Ex3: Radiation- There is a dog by the fire place, the dog is being warmed- the heat from the fire is being transferred over to the dog

Hope this will help you with your homework :)

8 0
3 years ago
Read 2 more answers
The following four waves are sent along strings with the same
likoan [24]

Answer:

Explanation:

y_1 = (3 mm) sin(x - 3t)

comparing it with standard wave equation

y = A sin( ωt-kx )

we see  

ω = -3 , k = -1

velocity = ω / k

= 3

y_2 = (6 mm) sin(2x - t)

we see  

ω = -1 , k = -2

velocity = ω / k

= .5

y_3 = (1 mm) sin(4x - t)

we see  

ω = -1 , k = -4

velocity = ω / k

= .25

y_4 = (2 mm) sin(x - 2t)

we see  

ω = -2 , k = -1

velocity = ω / k

= 2

So greatest velocity to lowest velocity

y_1 = (3 mm) sin(x - 3t) ,  y_4 = (2 mm) sin(x - 2t) ,y_2 = (6 mm) sin(2x - t) ,  y_3 = (1 mm) sin(4x - t)

b )

Given the mass per unit length of wire the same , velocity is proportional to

√ T , where T is tension

so in respect of tension in the wire same order will exist for highest to lowest tension .

3 0
3 years ago
You apply a horizontal force of 200N against a 50kg couch. The force of friction between the couch and the floor is 180N. If the
Sergio039 [100]

Answer:

The kinetic energy gained is 40[J]

Explanation:

This is a problem that applies the work and energy conservation. We must analyze the initial and final positions as well as the forces that act on the couch during displacement.

The working and energy conservation theorem says:

E_{k1} + W_{1-2}= E_{k2}

The above equation tells us that kinetic energy plus the work done to move an object from one position to another will be equal to kinetic energy in the last position.

The kinetic energy in the initial position is zero since the couch is at rest, Ek1=0

The work will be given by the force that drives the couch multiplied by the distance, and the friction force that acts in the opposite direction to the displacement.

0+(200-180)*2= Ek2\\Ek2=20*2= 40 [J]

6 0
3 years ago
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