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Phoenix [80]
3 years ago
7

Approximate the area between the xxx-axis and h(x) = \dfrac{1}{7-x}h(x)= 7−x 1 ​ h, (, x, ), equals, start fraction, 1, divided

by, 7, minus, x, end fraction from x = 2x=2x, equals, 2 to x = 5x=5x, equals, 5 using a left Riemann sum with 333 equal subdivisions.
Mathematics
1 answer:
tiny-mole [99]3 years ago
5 0

Answer:

\dfrac{47}{60} sq. units.

Step-by-step explanation:

The given function is

h(x)=\dfrac{1}{7-x}

We need to find the area between x-axis and the given function from x=2 to x=5.

Left Riemann sum formula of area:

Area=\sum_{n=0}^{N-1}f(x_n)(\Delta x_n)

For given question,

Area=\sum_{n=2}^{5-1}f(x_n)(\Delta x_n)

Area=\sum_{n=2}^{4}f(x_n)(\Delta x_n)

Area=f(x_2)(3-2)+f(x_3)(4-3)+f(x_4)(5-4)

Now,

Area=\dfrac{1}{7-2}\times (1)+\dfrac{1}{7-3}\times (1)+\dfrac{1}{7-4}\times (1)

Area=\dfrac{1}{5}+\dfrac{1}{4}+\dfrac{1}{3}

Area=\dfrac{12+15+20}{60}

Area=\dfrac{47}{60}

Therefore, the required area is \dfrac{47}{60} sq. units.

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Answer:

Step-by-step explanation:

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26=4x+10

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Write these price increases in order from greatest to least<br> 2/3, 75%, 7 / 10, 62.5%, 0.5
In-s [12.5K]

Answer:

75, 7/10, 2/3, 62,5, .5

Step-by-step explanation:

75%=75%

7/10=70%

2/3=66.67%

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5 0
3 years ago
Jack drove to work in the morning at an average speed of 45 miles per hour. He returned home in the evening along the same route
Dmitry [639]

Answer:

Step-by-step explanation:

Let's say that the time it took him to get to work in the morning is  t hours. Then the time it took him to get home in the afternoon must be 1 - t hours. We know that for any trip, distance equals rate times time or d = rt . That means that the distance he drove to work is given by , but we also know that the distance he drove to get home must be the same distance, because he took the same route (and, presumably, no one picked up him house and moved it while he was at work) so for the trip home we can say  d = 30 × (1 - t) and since the distances are equal, we can say: 

45t = 30 × (1 - t)

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t = 2 /5 hour to drive to work at 45mph

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d = 45 ×(2/5) = 18miles

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3 years ago
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