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Phoenix [80]
3 years ago
7

Approximate the area between the xxx-axis and h(x) = \dfrac{1}{7-x}h(x)= 7−x 1 ​ h, (, x, ), equals, start fraction, 1, divided

by, 7, minus, x, end fraction from x = 2x=2x, equals, 2 to x = 5x=5x, equals, 5 using a left Riemann sum with 333 equal subdivisions.
Mathematics
1 answer:
tiny-mole [99]3 years ago
5 0

Answer:

\dfrac{47}{60} sq. units.

Step-by-step explanation:

The given function is

h(x)=\dfrac{1}{7-x}

We need to find the area between x-axis and the given function from x=2 to x=5.

Left Riemann sum formula of area:

Area=\sum_{n=0}^{N-1}f(x_n)(\Delta x_n)

For given question,

Area=\sum_{n=2}^{5-1}f(x_n)(\Delta x_n)

Area=\sum_{n=2}^{4}f(x_n)(\Delta x_n)

Area=f(x_2)(3-2)+f(x_3)(4-3)+f(x_4)(5-4)

Now,

Area=\dfrac{1}{7-2}\times (1)+\dfrac{1}{7-3}\times (1)+\dfrac{1}{7-4}\times (1)

Area=\dfrac{1}{5}+\dfrac{1}{4}+\dfrac{1}{3}

Area=\dfrac{12+15+20}{60}

Area=\dfrac{47}{60}

Therefore, the required area is \dfrac{47}{60} sq. units.

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