All categories

3 years ago

Quadrilateral IJKL is similar to quadrilateral MNOP. Find the measure of side NO. Round your answer to the nearest tenth.

Mathematics

2 answers:

bulgar [2K]3 years ago

6 0

Answer:

Quadrilateral DEFG is similar to quadrilateral HIJK. Find the measure of side KH. Round your answer to the nearest tenth. Figures are not drawn to scale.

Step-by-step explanation:

Thepotemich [5.8K]3 years ago

5 0

Answer:

$NO = 66.9$

Step-by-step explanation:

Given

See attachment for quadrilaterals IJKL and MNOP

Required

Determine the length of NO

From the attachment, we have:

$KL = 9$

$JK = 14$

$OP = 43$

To do this, we make use of the following equivalent ratios:

$JK : KL = NO : OP$

Substitute values for JK, KL and OP

$14 : 9 = NO : 43$

Express as fractions

$\frac{14}{9} = \frac{NO}{43}$

Multiply both sides by 43

$43 * \frac{14}{9} = \frac{NO}{43}*43$

$43 * \frac{14}{9} = NO$

$\frac{43 * 14}{9} = NO$

$\frac{602}{9} = NO$

$66.8889 = NO$

$66.9 = NO$ --- approximated

$NO = 66.9$

You might be interested in

A community pool that is shaped like a regular pentagon needs a new cover for the winter months. The radius of the pool is 20.10

boyakko [2]

Answer:

$960.42\text{ ft}^2$

Step-by-step explanation:

Please find the attachment.

We have been given that a community pool that is shaped like a regular pentagon needs a new cover for the winter months.

To find the area of community pool we will use area of pentagon formula.

$\text{Area of pentagon}=\frac{1}{2}a*p$ , where, a represents the apothem or perpendicular distance from the center of the pentagon and p represents perimeter of pentagon.

Let us find the perimeter of our given pentagon by multiplying each side length by 5.

$\text{Perimeter of community pool}=5\times 23.62$

$\text{Perimeter of community pool}=118.1$

Now let us find apothem of our pentagon by using Pythagoras theorem.

$a^2=20.10^2-11.81^2$

$a^2=404.01-139.4761$

$a^2=264.5339$

$a=\sqrt{264.5339}$

$a=16.2645$

Upon substituting our given values in above formula we will get,

$\text{Area of community pool}=\frac{1}{2}\times 16.2645\times 118.1$

$\text{Area of community pool}=8.13224907\times 118.1$

$\text{Area of community pool}=960.418615627971\approx 960.42$

Therefore, the area of the pool that needs to be covered is 960.42 square feet.

3 0

3 years ago

Read 2 more answers

3,6,10,5, 16,3,6 Mean is 7 Median what’s the median? and is the mean correct?

mamaluj [8]

Answer:

Mean:7 Median:6

Step-by-step explanation:

Okay so the Median is 6, and the mean is correct.

6 0

3 years ago

Read 2 more answers

The ages of Edna, Ellie, and Elsa are consecutive integers. The sum of their ages is 108. What are their ages?

diamong [38]

All I did was guess and check. I started with the 30s because their sum would be nine and there might be a one to carry to make it 10. After many tries (well, not many, I'm just being dramatic) I got 35, 36, and 37. Hope I helped.

7 0

3 years ago

What happens to the sign or signs of the coordinates when you reflect a point?

elena55 [62]

Part a: Reflecting a point across the x-axis, changes the sign of the y-coordinate.

Part b: Reflecting a point across the y-axis, changes the sign of the x-coordinate.

Part c: Reflecting a point across both the axes, changes the signs of both the coordinates.

Explanation:

Part a: Reflecting a point across the x-axis

The reflection is a transformation of a figure which represents a flip.

The rule for a reflection over the x -axis is given by

$(x, y) \rightarrow(x,-y)$

Hence, this represents the change of sign of the y-coordinate.

Thus, Reflecting a point across the x-axis, changes the sign of the y-coordinate.

Part b: Reflecting a point across the y-axis

The rule for a reflection over the y -axis is given by

$(x, y) \rightarrow(-x, y)$

Hence, this represents the change of sign of the x-coordinate.

Thus, Reflecting a point across the y-axis, changes the sign of the x-coordinate.

Part c: Reflecting a point across both the axes

The rule for a reflection across both the axes is given by

$(x, y) \rightarrow(-x, -y)$

Hence, this represents the changes the signs of both the coordinates.

Thus, Reflecting a point across both the axes, changes the signs of both the coordinates.

6 0

3 years ago

How do i find the median in this question.

Korolek [52]

eu9ewg0u8wei08

Step-by-step explanation:

jiwfoiqwfqeoufhqeio0hfqifh0qoio

4 0

3 years ago