How does the energy in the light of the aurora borealis compare to the energy as an excited electron returns to its original ene
2 answers:
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Answer:
x = 0.40 m
Explanation:
- When the displacement is maximum, the particle is momentarily at rest, which means that at this point (assuming no friction present) all the mechanical energy is elastic potential, which can be written as follows:
- Since in absence of friction, total mechanical energy must keep constant, this means that at any time, the sum of the kinetic and potential energy, must be equal to (1), as follows:
- If KEf = U/2f, replacing in (2), we get:
- At any point, the elastic potential energy is given by the following expression:
where k= spring constant (N/m) and x is the displacement from the
equilibrium position.
- Replacing (4) in (3), simplifying and rearranging, we get:
- Finally, solving for x, we get: