if a car is traveling at an average speed of 60 kilometers per hour, how long does it take to travel 12 kilometers?

A small block has constant acceleration as it slides down a frictionless incline. The block is released from rest at the top of

Alchen [17]

Answer:

The speed of the block when it is 5.00 m from the top of the incline is 3.04 m/s

Explanation:

given information:

s = 7.80 m

v = 3.8 m/s

if s = 5 m, v?

first we have to find the acceleration of the block using the following equation:

v² = v₀² + 2as, v₀² = 0 thus

3.8² = 2 a 7.8

a = 0.93

so, if s = 5m the final speed is

v² = 2 (0.93) (5)

= 9.26

v = √9.26

= 3.04 m/s

5 0

4 years ago

a pitcher throws a softball toward the home plate. when the ball hits the catchers mitt its horizontal velocity is 32 meters/sec

lora16 [44]

F = (mass)(acceleration) = ma

m = 0.2 kg

Vi = 32 m/s

t = 0.5 s

Vf = 0 m/s (since it was put to stop)

a=(Vf-Vi)/t

a=(0-32)/0.5

a = 64 m/s^2 (decelerating)

F = ma = (0.2 kg)(64 m/s^2)

F = 12.8 N

<span>Hope this answer will be a good h<span>elp for you.</span></span>

8 0

3 years ago

Read 2 more answers

One day on her walk home from school, Leann noticed some rust on an old car Leann knows that when iron and oxygen chemically rea

Katena32 [7]

Answer:

reactants

Explanation:

The reaction model is given as shown below:

4Fe + 3O₂ → 2Fe₂O₃

The name that describes the iron and oxygen found on the left hand side of Leann's model is reactants.

Reactants in a chemical expression are the species that are combining together to give a product.

Some reactions only have one reactant and such a chemical process is often termed decomposition reaction.

The two moles of Fe₂O₃ is the product of the reaction.

4 0

3 years ago

assume that the initial speed is 25 m/s and the angle of projection is 53 degree above the hroizontal. the cannon ball leaves th

finlep [7]

Answer:

A. xmax = 131.49 m

B. t = 8.74 s

C. ymax = 220.33 m

Explanation:

A. In order to find the horizontal distance which cannon travels you first calculate the flight time. The flight time can be calculated by using the following formula:

$y=y_o+v_osin\theta-\frac{1}{2}gt^2$ (1)

yo: height from the projectile is fired = 200m

vo: initial velocity of the projectile = 25m/s

g: gravitational acceleration = 9.8 m/s^2

θ: angle between the direction of the initial motion of the ball and the horizontal = 53°

t: time

You need the value of t when the projectile hits the ground. Then, in th equation (1) you make y = 0m.

When you replace the values of all parameters in the equation (1), you obtain the following quadratic formula:

$0=200+(25)sin53\°t-\frac{1}{2}(9.8)t^2\\\\0=200+19.96t-4.9t^2$ (2)

You use the quadratic formula to obtain the value of t:

$t_{1,2}=\frac{-19.96\pm\sqrt{(19.96)^2-4(-4.9)(200)}}{2(-4.9)}\\\\t_{1,2}=\frac{-19.96\pm65.71}{-9.8}\\\\t_1=8.74s\\\\t_2=-4.66s$

You use the positive value because it has physical meaning.

Now, you can calculate the horizontal range of the projectile by using the following formula:

$x_{max}=v_ocos\theta t$

$x_{max}=(25m/s)(cos53\°)(8.74s)=131.49m$

The cannon ball travels a horizontal distance of 131.49 m

B. The cannon ball reaches the canon for t = 8.74s

C. The maximum height is obtained by using the following formula:

$y_{max}=y_o+\frac{v_o^2sin^2\theta}{2g}$ (3)

By replacing in the equation (3) the values of all parameters you obtain:

$y_{max}=200m+\frac{(25m/s)^2(sin53\°)^2}{2(9.8m/s^2)}\\\\y_{mac}=200m+20.33m=220.33m$

The maximum height reached by the cannon ball is 220.33m

3 0

3 years ago

What is the value of -2 + 100 - (-50)?

taurus [48]

I believe the value of -2+100-(50)=148. Hope this helps

3 0

3 years ago