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Klio2033 [76]
3 years ago
9

Please help me with 8,9,10,11

Chemistry
1 answer:
Gwar [14]3 years ago
8 0

Answer:

8. The particles have the same volume in each container (not so sure about number 8 )  9. Solid  10. Gas 11. Temperature and Pressure

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In which of the following types of solution is the rate of dissociation equal to the rate of crystallization? Concentrated Super
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In a <u>Saturated </u>solution, the rate of dissociation equal to the rate of crystallization

Explanation:

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Non metal are usually poor conductor of hart and electricity . The are non -lustourous,non-sonours,non-malleable and are coloure
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7 0
3 years ago
How many traditional areas of study can chemistry be divided into
seraphim [82]
<span>There is five main area of study in Chemistry, these are:

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6 0
3 years ago
A sample of He gas (3.0 L) at 5.6 atm and 25°C was combined with 4.5 L of Ne gas at 3.6 atm and 25°C at constant temperature in
In-s [12.5K]

Answer:

3.6667

Explanation:

<u>For helium gas:</u>

Using Boyle's law  

{P_1}\times {V_1}={P_2}\times {V_2}

Given ,  

V₁ = 3.0 L

V₂ = 9.0 L

P₁ = 5.6 atm

P₂ = ?

Using above equation as:

{P_1}\times {V_1}={P_2}\times {V_2}

{5.6}\times {3.0}={P_2}\times {9.0} atm

{P_2}=\frac {{5.6}\times {3.0}}{9.0} atm

{P_1}=1.8667\ atm

<u>The pressure exerted by the helium gas in 9.0 L flask is 1.8667 atm</u>

<u>For Neon gas:</u>

Using Boyle's law  

{P_1}\times {V_1}={P_2}\times {V_2}

Given ,  

V₁ = 4.5 L

V₂ = 9.0 L

P₁ = 3.6 atm

P₂ = ?

Using above equation as:

{P_1}\times {V_1}={P_2}\times {V_2}

{3.6}\times {4.5}={P_2}\times {9.0} atm

{P_2}=\frac {{3.6}\times {4.5}}{9.0} atm

{P_1}=1.8\ atm

<u>The pressure exerted by the neon gas in 9.0 L flask is 1.8 atm</u>

<u>Thus total pressure = 1.8667 + 1.8 atm = 3.6667 atm.</u>

6 0
3 years ago
All gases are considered to be ____.
NISA [10]

Answer:

B

Explanation:

I used my notes from class today.

3 0
3 years ago
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