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Murrr4er [49]
2 years ago
5

Which consumers are cornivores

Chemistry
2 answers:
QveST [7]2 years ago
5 0

Answer:

Secondary consumers

Explanation:

hope this helps

Rus_ich [418]2 years ago
5 0

Answer:

Carnivores and omnivores are secondary consumers. Many carnivores eat herbivores. Some eat omnivores, and some eat other carnivores. Carnivores that consume other carnivores are called tertiary consumers.

E.g

Felines, ranging from domestic cats to lions, tigers, and other large predators.

Some canines, such as the Gray Wolf

Hyenas.

ferrets.

Polar Bears.

Pinnipeds ( seals, sea lions, walruses, etc.)

Birds of prey, including hawks, eagles, falcons, and owls.

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What is the number of protons of oxygen
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What equation is the relationship between wavelength and frequency?
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The equilibrium constant, Kc, for the following reaction is 1.29E-2 at 600 K. COCl2(g) CO(g) Cl2(g) Calculate the equilibrium co
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Answer:

At Equilibrium

[COCl₂] = 0.226 M

[CO] = 0.054 M

[Cl₂] = 0.054 M

Explanation:

Given that;

equilibrium constant Kc = 1.29 × 10⁻² at 600k

the equilibrium concentrations of reactant and products = ?

when 0.280 moles of COCl2(g) are introduced into a 1.00 L vessel at 600 K. [COCl²]

Concentration of  COCl₂ = 0.280 / 1.00 = 0.280 M

COCl₂(g) ---------->  CO(g)   +  Cl₂(g)

0.280                      0                0  ------------ Initial

-x                             x                 x

(0.280 - x)               x                 x   ----------- equilibrium

we know that; solid does not take part in equilibrium constant expression

so

KC = [CO][Cl₂] / COCl₂

we substitute

1.29 × 10⁻² = x² / (0.280 - x)

0.0129 (0.280 - x) = x²

x² = 0.003612 - 0.0129x

x² + 0.0129x - 0.003612 = 0

x = -b±√(b² - 4ac) / 2a

we substitute

x = [-(0.0129)±√((0.0129)² - 4×1×(-0.003612))] / [2 × 1 ]

x = [-0.0129 ± √( 0.00017 + 0.01445)] / 2

x = [-0.0129 ± 0.1209] / 2

Acceptable value of x =[ -0.0129 + 0.1209] / 2

x = 0.108 / 2

x = 0.054

At equilibrium

[COCl₂] = (0.280 - x) = 0.280 - 0.054 = 0.226 M

[CO] = 0.054 M

[Cl₂] = 0.054 M

7 0
3 years ago
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