All categories

3 years ago

What does sodium react with

Chemistry

1 answer:

Pani-rosa [81]3 years ago

5 0

Sodium reacts with water to form a colorless solution of sodium hydroxide and hydrogen gas.

You might be interested in

5.50 L of a 0.190 M CaCl2M CaCl2 solution<br> How do you find Grams?

Firdavs [7]

Answer:

115.891

Explanation:

Molarity is equal to moles/liters so to get moles we multiply molarity by liters, after this we multiply the moles by the total atomic weight of the compound to get grams

6 0

3 years ago

I just need 4-8! Plz hurry!!!!!!!!!!!

RSB [31]

Answer:

4: 90N

5: 7.77777m/s

6: 4

7: 12.5609756098

8: 187.5

Explanation:

8 0

3 years ago

For the overall reaction below, which of the following is the correctly written rate law? Overall reaction: O3(g)+2NO2(g)→N2O5(g

zavuch27 [327]

Answer: $Rate=k[O_3][NO_2]^2$

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

$O_3(g)+NO_2(g)\rightarrow NO_3(g)+O_2(g)$ slow

$NO_3(g)+NO_2(g)\rightarrow N_2O_5(g)$ fast

To determine the net chemical equation, we will simply add the above two equations, we get:

$O_3(g)+2NO_2(g)\rightarrow N_2O_5(g)+O_2(g)$

$Rate=k[O_3][NO_2]^2$

Order with respect to $O_3$ is 1 and Order with respect to $NO_2$ is 2.

Thus the rate law will be: $Rate=k[O_3][NO_2]^2$

6 0

3 years ago

Acetylene (C2H2), an important fuel in welding, is produced in the laboratory when calcium carbide (CaC2) reacts with water: CaC

Anastaziya [24]

Answer:

There are 1.287 grams of acetylene collected

Explanation:

Total gas pressure = 909 mmHg

Vapor pressure of water = 20.7 mmHg

Pressure of acetylene = 909 mmHg - 20.7 mmHg = 888.3 mmHg

1mmHg = 1 torr

22 ° C + 273.15 = 295.15 Kelvin

Ideal gas law ⇒ pV = nRT

⇒ with p = pressure of the gas in atm

⇒ with V = volume of the gas in L

⇒ with n = amount of substance of gas ( in moles)

⇒ with R = gas constant, equal to the product of the Boltzmann constant and the Avogadro constant (62.36 L * Torr *K^−1 *mol^−1)

⇒ with T = absolute temperature of the gas (in Kelvin)

888.3 torr * 1.024 L = n * 62.36 L * Torr *K^−1 *mol^−1 * 295.15 K

n = 0.04942 moles of C2H2

Mass of C2H2 = 0.04942 moles x 26.04 g/mole = 1.287 g

There are 1.287 grams of acetylene collected

6 0

3 years ago

Suppose that Daniel has a 3.00 3.00 L bottle that contains a mixture of O 2 O2 , N 2 N2 , and CO 2 CO2 under a total pressure of

Alenkinab [10]

Answer:

Partial pressure O₂ → 2.74 atm

Explanation:

Let's analyse the data given:

Volume → 3L

In the bottle there is a mixture of gases that contains, O₂, N₂ and CO₂.

Total pressure is 4.80 atm

Let's apply the Ideal Gases Law to determine the total moles of the mixture

P . V = n . R. T

4.80 atm . 3L = n . 0.082 . 273K

n = 4.80 atm . 3L / 0.082 . 273K → 0.643 moles

We apply the concept of mole fraction:

Mole fraction of a gas X = moles of gas X / Total moles

Mole fraction of a gas X = Partial pressure X / Total pressure

In a mixture, sum of mole fraction of each gas = 1

We determine mole fraction of N₂ → 0.230 / 0.643 = 0.357

We determine mole fraction of CO₂ → 0.350 atm / 4.80 atm = 0.0729

1 - mole fraction N₂ - mole fraction CO₂ = mole fraction O₂

1 - 0.357 - 0.0729 = 0.5701 → mole fraction O₂

We replace in the formula: Mole fraction O₂ = Partial pressure O₂ / 4.80 atm

0.5701 . 4.80 atm = Partial pressure O₂ → 2.74 atm

5 0

3 years ago

Read 2 more answers