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Tatiana [17]
3 years ago
12

How old is the earth in millions of years

Chemistry
2 answers:
Paul [167]3 years ago
6 0
A million years old
Duhhhh
Stella [2.4K]3 years ago
5 0

Answer:

<h3><em><u>4.543</u></em><em><u> </u></em><em><u>billion</u></em><em><u> </u></em><em><u>years</u></em><em><u> </u></em><em><u>(</u></em><em><u> </u></em><em><u>approx</u></em><em><u> </u></em><em><u>)</u></em></h3>

<em><u>50</u></em><em><u> </u></em><em><u>million</u></em>

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What have the scientific studies identified as the major cause of acid rain in the united states?
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Sulfur dioxide (SO2) and nitrogen oxides (NOx) released into the air by fossil-fuel power plants, vehicles and oil refineries are the biggest cause of acid rain today, according to the EPA.

Explanation:

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How many atoms it would take to make up the thickness of a banknote.
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Since one banknote has a thickness of about 0.1 millimeters, if all the banknotes produced in a year were stacked up, they would reach a height of approximately 300 kilometers, which is about 80 times the height of Mount Fuji.

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Even though the neighborhood shown by the green star was not next to any of these fires, how was the neighborhood affected by th
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if a sample of gas at 25.2 c has a volume of 536mL at 637 torr, what will its volume be if the pressure is increased to 712 torr
nignag [31]
Considering ideal gas:
PV= RTn

T= 25.2°C = 298.2 K

P1= 637 torr = 0.8382 atm

V1= 536 mL = 0.536 L

:. R=0.082 atm.L/K.mol

:. n= (P1V1)/(RT) = ((0.8382 atm) x (0.536 L))/
((0.082 atmL/Kmol) x (298.2K))

:. n= O.0184 mol

Then,
P2= 712 torr = 0.936842 atm

V2 = RTn/P2 = [(0.082atmL/
Kmol) x (298.2K) x (0.0184mol) ]/(0.936842atm)

:.V2 = 0.4796 L
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6 0
3 years ago
If a sample containing 18.1 g of NH3 is reacted with 90.4 g of
USPshnik [31]

Answer:

3.64g

Explanation:

Given parameters:

Mass of NH₃  = 18.1g

Mass of Cu₂O  = 90.4g

Unknown:

Limiting reactant  = ?

Mass of N₂ formed  = ?

Solution:

The reaction equation is given as:

       Cu₂O + 2NH₃ → 6Cu + N₂ + 3H₂O

The limiting reactant is the one in short supply in the reaction. Let us find the number of moles of the given species;

  Number of moles = \frac{mass}{molar mass}  

Molar mass of Cu₂O = 2(63.6) + 16  = 143.2g/mol

Molar mass of NH₃  = 14 + 3(1) = 17g/mol

Number of moles of Cu₂O = \frac{18.1}{143.2}   = 0.13moles

Number of moles of NH₃   = \frac{90.4}{17}   = 5.32moles

  From this reaction;

       1 mole of  Cu₂O combines with 2 mole of NH₃

So   0.13moles of  Cu₂O will combine with 0.13 x 2 mole of NH₃

                                              = 0.26moles of NH₃

Therefore, Cu₂O is the limiting reactant. Ammonia is in excess;

Mass of N₂;

   Mass = number of moles x molar mass

    1 mole of Cu₂O  will produce 1 mole of N₂

    0.13 mole of Cu₂O  will produce 0.13 mole of N₂

    Mass  = 0.13 x (2 x 14) = 3.64g

5 0
3 years ago
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