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pantera1 [17]
3 years ago
5

5. Palmer goes to L.A. one weekend. He has a bank account with a balance

Mathematics
1 answer:
dsp733 years ago
3 0

Answer:

$50

Step-by-step explanation:

To find the total amount that Palmer spent, you would first add up all his purchases. This can be represented by adding $90 + $110 + $100, which adds up to $300.

To find out how much Palmer has left, just subtract $300 from his initial $350 ($350 - $300 = $50.) This gives you a final answer of Palmer having $50 in his bank account.

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kondaur [170]
59,317 I dno how to explain it but it may be wrong you should do the math yourself to check..
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What’s 50 1/3+ 50 1/3?
slega [8]

Answer:

100 2/3

Step-by-step explanation:

50+50=100

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What is the system of inequalities associated with the following graph?
slamgirl [31]

One line passes through the points (-2,3) and (0,-3) , it means the y intercept is b=-3

and slope m = \frac{(-3-3)}{0-(-2)}

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And the inequality should be y\geq -3x-3

Or 3x +y \geq -3

And the other line passes through (-2,3) and (0,2)

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Or

2y +x \leq 4

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6 0
3 years ago
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Find the measure of each missing angle.
nadya68 [22]

Answer:

Step-by-step explanation:

Angle sum property of triangle: Sum of all the angles of a triangle is 180

Alternate interior angles: When two parallel lines are intersected by a transversal, the pair of angles on the inner side of  each of these lines but on the opposite side of the transversal are called  alternate interior angles

In ΔABC,

  ∠1 + 90 + 38 = 180    {angle sum property of triangle}

         ∠1 + 128 =  180

               ∠1     = 180 - 128

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AB // CD and AC is transversal.

 \sf \boxed{\bf  \angle 3 = 38^\circ}   {Alternate interior angles are equal}

In ΔACD,

      ∠2 + ∠3 + 63 = 180 {angle sum property of triangle}

       ∠2 + 38 +63  = 180

               ∠2  + 101 =180

                         ∠2 = 180 - 101

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5 0
1 year ago
Please help me with this math question​
scZoUnD [109]

Answer:

<h2>d : e : f = 4 : 3 : 6</h2>

Step-by-step explanation:

\bold{METHOD\ 1}\\\\6d=8e\qquad\text{divide both sides by 6}\\\\d=\dfrac{8}{6}e\to d=\dfrac{4}{3}e\\\\\text{Substitute it and}\ f=2e\ \text{to the ratio}\ d:e:f:\\\\\dfrac{4}{3}e:e:2e\qquad\text{cancel}\ e\\\\\dfrac{4}{3}:1:2\qquad\text{multiply by 3}\\\\\huge\boxed{4:3:6}

\bold{METHOD\ 2}\\\\6d=8e\qquad\text{divide both sides by 6}\\\\d=\dfrac{8}{6}e\qquad\text{divide both sides by}\ e\neq0\\\\\dfrac{d}{e}=\dfrac{4}{3}\to d:e=4:3\\\\2e=f\qquad\text{divide both sides by 2}\\\\e=\dfrac{f}{2}\to e=\dfrac{1}{2}f\qquad\text{divide both sides by}\ f\neq0\\\\\dfrac{e}{f}=\dfrac{1}{2}\to e:f=1:2\\\\\text{We have}\ d:e=4:3\ \text{and}\ e:f=1:2.

\text{We know}\ \dfrac{1}{2}=\dfrac{1\cdot3}{2\cdot3}=\dfrac{3}{6}\\\\\text{threfore}\ e:f=3:6\\\\\text{Now we have}\\\\\left\begin{array}{ccc}d:e=4:3\\e:f=3:6\end{array}\right\}\large{\boxed{d:e:f=4:3:6}}

6 0
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