Using a graph, table of values, and/or equations solve the following problem.
1 answer:
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Answer:
110.5 yd²
Step-by-step explanation:
Separate the figure into 1 triangle and 3 rectangles.
(see attached image)
<u>Area 1</u>
Area of a triangle = 1/2 × base × height
= 1/2 × (7 + 2 + 2) × 7
= 1/2 × 11 × 7
= 38.5 yd²
<u>Area 2</u>
Area of a rectangle = width × length
= 3 × (5 + 2 + 2)
= 3 × 9
= 27 yd²
<u>Area 3</u>
Area of a rectangle = width × length
= 5 × (5 + 2)
= 5 × 7
= 35 yd²
<u>Area 4</u>
Area of a rectangle = width × length
= 2 × 5
= 10 yd²
<u>Total Area</u>
Area 1 + Area 2 + Area 3 + Area 2 = 38.5 + 27 + 35 + 10
= 110.5 yd²
The value of two arithmetic means which are inserted between 3 and 24 are 24/9 and 75/9.
<h3>What is arithmetic mean?</h3>Arithmetic mean is the mean or average which is equal to the ratio of sum of all the group numbers to the total numbers.
The two arithmetic means between 3 and 24 are has to be inserted.
3, A₂, A₃, 24
All the four numbers are in arithmetic progression. The nth terms of AM can be found using the following formula:
t(n)=a(n-1)d
Here, d is the common difference a is the first terms and n is the total term. The first term, a=3 and t₄=24. Thus, the common difference is;
The second and 3rd term are:
Thus, the value of two arithmetic means which are inserted between 3 and 24 are 24/9 and 75/9.
Learn more about the arithmetic mean here;
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